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STatiana [176]
3 years ago
6

Which sign makes this number sentence true?

Mathematics
1 answer:
Karolina [17]3 years ago
8 0

Answer:

its D

Step-by-step explanation:

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A number decreased by the product of 6 and 3
saw5 [17]

Answer:

nine

4 0
3 years ago
Read 2 more answers
A gumball machine has 450 red gumballs, if the red gum balls are 75 of the total number of gum balls
jeka94

Answer:

450-75=375

Step-by-step explanation:

first you write 450 because its total of red gumballs

then you are going to take away 75 of 450

finaly you get 450-75=375

(four hundred and fifty take away seventy five equals three hundred and seventy five)

7 0
3 years ago
The least common multiple of two numbers is 60 and one of the numbers is seven less than the other number what are the numbers
mihalych1998 [28]
53 or it could be 60 multiply common multiple
6 0
4 years ago
The graph of f(x) = x6 – 2x4 – 5x2 + 6 is shown below.
DochEvi [55]

Answer:

There are two rational roots for f(x)

Step-by-step explanation:

We are given a function

f(x) = x^6-2x^4-5x^2+6

To find the number of rational roots for f(x).

Let us use remainder theorem that when

f(a) =0, (x-a) is a factor of f(x) or x=a is one solution.

Substitute 1 for x

f(1) = 1-2-5+6=0

Hence x=1 is one solution.

Let us try x=-1

f(-1) = 1-2-5+6 =0

So x =-1 is also a solution and x+1 is a factor

We can write f(x) by trial and error as

f(x) = (x-1)(x+1)(x^2-3)

We find that f(x) (x^2-3) factor gives two irrational solutions as

±√3.

Hence number of rational roots are 2.

5 0
3 years ago
Read 2 more answers
Let f be a continuous function defined on the interval [0,1] such that f(0) = f(1). Show that there exists a number 0 <= a &l
Leni [432]

Explanation:

In order to prove that affirmation, we define the function g over the interval [0, 1/2] with the formula g(x) = f(x+1/2)-f(x) .

If we evaluate g at the  endpoints we have

g(0) = f(1/2)-f(0) = f(1/2) - f(1) (because f(0) = f(1))  

g(1/2) = f(1) - f(1/2) = -g(0)

Since g(1/2) = -g(0), we have one chance out of three

  • g(0) > 0 and g(1/2) < 0
  • g(0) < 0 and g(1/2) > 0
  • g(0) = g(1/2) = 0

We will prove that g has a zero on [0,1/2]. If g(0) = 0, then it is trivial. If g(0) ≠ 0, then we are in one of the first two cases, and therefore g(0) * g(1/2) < 0. Since f is continuous, so is g. Bolzano's Theorem assures that there exists c in (0,1/2) such that g(c) = 0.  This proves that g has at least one zero on [0,1/2].

Let c be a 0 of g, then we have

0 = g(c) = f(c+1/2)-f(c)

Hence, f(c+1/2) = f(c) as we wanted.

5 0
3 years ago
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