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liq [111]
3 years ago
11

Y = (x - 1)2 – 6y = 4x + 10Answer As Corrdinates PLEASE HELP ​

Mathematics
1 answer:
AleksAgata [21]3 years ago
5 0

Answer:

(-9, -26)

Step-by-step explanation:

y = (x - 1)2 - 6 and y = 4x + 10

Since they are both y =, you can set the two equations equal to each other:

(x - 1)2 - 6 = 4x + 10

2x - 2 - 6 = 4x + 10

-2 - 6 = 2x + 10

-8 = 2x + 10

2x = -18

x = -9

Check:

y = (x - 1)2 - 6

y = (-9 - 1)2 - 6

y = -18 - 2 - 6

y = -26

y = 4x + 10

y = 4 (-9) + 10

y = -36 + 10

y = -26

The answer to these equations is (-9, - 26). If you graph this, this is the point where the two graphs intersect.

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When you add two integers with the same sign, do
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8 0
3 years ago
A bee flies at 9 feet per second directly to a flowerbed from its hive. The bee stays at the flowerbed for 13 ​minutes, and then
Kobotan [32]

Complete Question

A bee flies at 9 feet per second directly to a flowerbed from its hive. The bee stays at the flowerbed for 13 ​minutes, and then flies directly back to the hive at 6 feet per second. It is away from the hive for a total of 16 minutes. What equation can you use to find the distance of the flowerbed from the hive?

Answer:

The equation is 960  = \frac{Z}{9}+ \frac{Z}{6} + 780

Step-by-step explanation:

From the question we are told that

The velocity of the bee is v =  9ft/s =

The duration on the flowerbed is t =  13 \  minutes  =  780 \  s

The velocity back to his hive is u = 6ft / s

The total time away from it hive is t_t  =  16 \  minutes  =  960  \ s

Now let assume the distance of the flower bed from the hive is Z

Generally the time taken for the bee to travel to the flower bed from its hive is

t_1 =  \frac{Z}{9}

The time taken for the bee to fly back to his hive is

t_2 =  \frac{Z}{6}

Generally the total time the bee spent outside of his house is mathematically represented as

t_t  =  t_1 + t_2 +  t

=> 960  = \frac{Z}{9}+ \frac{Z}{6} + 780

6 0
3 years ago
Find S20 for the geometric series 4 + 12 + 36 + 108 + … 5,034,043,187 5,123,498,245` 6,973,568,800 7,321,089,348
yan [13]
A_{1} = 4
a_{2} = 12

a_{2} = a_{1}*q
12 = 4q
q = 3

S20 = a_{1}*\frac{(q^{20}-1)}{(q-1)}

S20 = 4*\frac{(3^{20}-1)}{3-1}

S20 = 4*\frac{3486784401-1}{2}

S20 = 2*3486784400

S20 = 6,973,568,800
8 0
3 years ago
A 10.0kg rock is dropped and hits the ground below at a speed of 60 m/s . Calculate the gravitational potential energy of the ro
disa [49]

Answer:

Solution:

Mass of body, m= 10kg

velocity, v= 60m/s

Now,kinetic energy on earth= potential energy at a that point [energy conservation]

so, kinetic energy= 1/2*m* v^2

= 1/2* 60(60)^2

= 30* 60*60

= 108000 joules

7 0
3 years ago
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