Answer:
(9.5, 0) is in quadrant I. (-4, 7) is in quadrant II. (-1, -8) is in quadrant III.
Step-by-step explanation:
The negative signs say everything (quite literally). If there are no negative signs, it is in quadrant I. If there is one in the x-axis (the first number in an ordered pair), it is in quadrant II. If there are 2 negative signs, it is in quadrant III, and if there is one in the y-axis (the second number in an ordered pair), it is in quadrant IV.
Answer:
(-9.5, -4)
Step-by-step explanation:
Given the ratio a:b (a to b) of two segments formed by a point of partition, and the endpoints of the original segment, we can calculate the point of partition using this formula:
.
Given two endpoints of the original segment
→ (-10, -8) [(x₁, y₁)] and (-8, 8) [(x₂, y₂)]
Along with the ratio of the two partitioned segments
→ 1 to 3 = 1:3 [a:b]
Formed by the point that partitions the original segment to create the two partitioned ones
→ (x?, y?)
We can apply this formula and understand how it was derived to figure out where the point of partition is.
Here is the substitution:
x₁ = -10
y₁ = -8
x₂ = -8
y₂ = 8
a = 1
b = 3
. →
→
→
→
→
→
→
*
*
Now the reason why this
Answer:
Step-by-step explanation:
The best way to do this is to use your LCM and eliminate the fractions. To find the LCM you have to use all the denominators as a multiplier so the denominator in each term cancels out. We will first factor the x-squared term to simplify and see what 2 factors are hidden there.
factors to (x + 2)(x - 2). That means that our 3 denominators that make up our LCM are x(x+2)(x-2). We will mulitply that in to each term in our rational equation, canceling out the denominators where applicable.
![x(x+2)(x-2)[\frac{2}{(x-2)}+\frac{7}{(x-2)(x+2)}=\frac{5}{x}]](https://tex.z-dn.net/?f=x%28x%2B2%29%28x-2%29%5B%5Cfrac%7B2%7D%7B%28x-2%29%7D%2B%5Cfrac%7B7%7D%7B%28x-2%29%28x%2B2%29%7D%3D%5Cfrac%7B5%7D%7Bx%7D%5D)
In the first term, the (x-2) will cancel leaving us with
x(x+2)[2] which simplifies to
![x^2+2x[2]](https://tex.z-dn.net/?f=x%5E2%2B2x%5B2%5D)
In the second term, the (x+2)(x-2) cancels out leaving us with
x[7].
In the last term, the x cancels out leaving us with
(x+2)(x-2)[5] which simplifies to
![x^2-4[5]](https://tex.z-dn.net/?f=x%5E2-4%5B5%5D)
Now we will distribute through each cancellation:
2x²+4x;
7x;
5x²-20
Putting them all together we have
2x² + 4x + 7x = 5x² - 20
Combining like terms gives us a quadratic:
3x² - 11x - 20 = 0
Factor that however you find it easiest to factor quadratics and get that
x = 5 and x = -4/3
The answer is:
[C]: 61.38 cm .
_______________________________________________Note: A =

²
300 = (3.14) * r² ;
______________________
Divide each side by "3.14" ;
r² = 300/3.14 ;
r² = 95.5414012738853503 ;
√r² = √(95.5414012738853503) ;
r = 9.7745281867661188048
Circumference, "C" =

* d ; (d = diameter = 2*r);
C = 2*

*r ;
C = 2*(3.14)*(9.7745281867661188048)
C = 61.384037012891226094144 ; which rounds to answer choice: [C]: 61.38 cm .________________________________________________________