Answer:
The 95% confidence interval for the mean of all body temperatures is between 97.76 ºF and 99.12 ºF
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 10 - 1 = 9
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2.2622
The margin of error is:
M = T*s = 2.2622*0.3 = 0.68
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 98.44 - 0.68 = 97.76 ºF
The upper end of the interval is the sample mean added to M. So it is 98.44 + 0.68 = 99.12 ºF
The 95% confidence interval for the mean of all body temperatures is between 97.76 ºF and 99.12 ºF
Answer: I cant see image!!!
Step-by-step explanation:
Answer:
wheres the question
Step-by-step explanation:
Hmmm if the question is about the triangle and the "top" angle, the answer will be c= 140.
Replace f(x) with 0 and swith the equation around to solve for x
x^4 - 32x^2 - 144 = 0
Factor the left side:
(x+6) (x-6) (x^2+4)
so far we have x+6 = 0, x = -6
x -6 = 0, x = 6
solve x^2 +4 = 0
x^2 = -4
x = sqrt(-4)
x = 2i, -21
The answer is B) 2i, 6, -6