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2 years ago

Write the equation of a line that is perpendicular to y=-2/7x+9 and passes through the point (4,-6)

2 answers:

6 0

This is in slope-intercept form, so you can think of it as being y=mx+b. Invert m (the slope) and flip its sign, and then substitute the x and y values in and solve for b. The answer is y=7/2x-20.

34kurt2 years ago

6 0

Answer:y=7/2 x-20

Step-by-step explanation: just took the khan academy quiz goodluck loves!

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In ΔJKL, the measure of ∠L=90°, KL = 22 feet, and JK = 54 feet. Find the measure of ∠J to the nearest degree.

nydimaria [60]

We have been given that in ΔJKL, the measure of ∠L=90°, KL = 22 feet, and JK = 54 feet. We are asked to find the measure of angle J to nearest degree.

First of all, we will draw a triangle as shown in the attachment.

We can see from our attachment that side KL is opposite side to angle J and side JK is hypotenuse of right triangle.

We know that sine relates opposite side of right triangle to hypotenuse.

$\text{sin}=\frac{\text{Opposite}}{\text{Hypotenuse}}$

$\text{sin}(\angle J)=\frac{22}{54}$

Using inverse sine or arcsin, we will get:

$\angle J=\text{sin}^{-1}(\frac{22}{54})$

$\angle J=24.042075905756^{\circ}$

Upon rounding to nearest degree, we will get:

$\angle J\approx 24^{\circ}$

Therefore, the measure of angle J is approximately 24 degrees.

8 0

2 years ago

Which angle is NOT coterminal with 110 degrees

Firlakuza [10]

830 degrees for sureee

3 0

2 years ago

PLEASE HELP! ASAP! no links please

adoni [48]

From left to right it’s 1, 49, 9, 70

7 0

2 years ago

Ms. Erickson is going to see the hot air balloons in Albuquerque, New Mexico.

maks197457 [2]

Answer:

Step-by-step explanation:

You have to multiply the top and bottom of the fraction (2/5) by 30 so the denominator will be 150. You also have to multiply the top by 30 (2 times 30). The answer is 60 will be rainbow colored!

2 x 30 = 60

5 x 30 = 150

3 0

2 years ago

A ball is dropped from a height of 192 inches onto a level floor. After the third bounce it is still 3 inches off the ground. Pr

ANEK [815]

Answer: The required fraction = $\dfrac18$

Step-by-step explanation:

Let the required fraction = $\dfrac{p}{q}$

Given: Initial height = 192 inches

Height of ball after second bounce = $\dfrac{p}{q}\times192$

Height of ball after third bounce = $\dfrac{p}{q}\times\dfrac{p}{q}\times192=192\dfrac{p^2}{q^2}$

After the third bounce it is 3 inches off the ground.

So,

$(\dfrac{p}{q})^2192=3\\\\\\(\dfrac{p}{q})^2=\dfrac{3}{192}\\\\(\dfrac{p}{q})^2=\dfrac{1}{64}\\\\(\dfrac{p}{q})^2=(\dfrac{1}{8})^2\\\\ \dfrac{p}{q}=\dfrac{1}{8}$

Hence, The required fraction = $\dfrac18$

5 0

2 years ago