Given the scores on a statewide standardized test are normally distributed
Mean = μ = 78
Standard deviation = σ = 3
Normalize the data using the z-score by using the following formula and chart:

Estimate the percentage of scores of the following cases:
(a) between 75 and 81
so, the z-score for the given numbers will be:

As shown, the percentage when (-1 < z < 1) = 68%
(b) above 87

The percentage when (z > 3) = 0.5%
(c) below 72

The percentage when (z < -2) = 0.5 + 2 = 2.5%
(d) between 75 and 84

The percentage when ( -1 < z < 2 ) = 68 + 13.5 = 81.5%
Answer:
x=-5
Step-by-step explanation:
since the y's cancel out, set the first equation equal to the second and solve like you'd normally do.
<em>Answer:</em>
<em>X = 9</em>
<em>Step-by-step explanation:</em>
<em>X + 12 = 4X - 15</em>
<em>12 + 15 = 4X - X</em>
<em>3X = 27</em>
<em>X = 27 : 3</em>
<em>X = 9</em>
The domain of the function given are:
y=cot x
{x∈R: πn<x<π(n+1)} where n any integer
y=csc x
{x∈R: πn<x<π(n+1)} where n any integer
y=cos x
R (all real numbers)
y=sec x
{x∈R:π(n+1/2)<x<π(n+3/2)} where n is all integers.
from above we see that the the function that has a domain of all real numbers except npi is y=cot x and y=csc x