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Ahat [919]
2 years ago
5

G(x)= l2xl +2 find domain and range

Mathematics
1 answer:
Romashka [77]2 years ago
3 0

The domain of the function g(x)=l2xl +2 is all real numbers and the range is from (0,∞).

Given g(x)= l2xl +2

First of all we know that modulas gives two values for x<0 and x>=0.

The function g(x) if opened gives two values.

for x>=0 g(x)=2x+2

for x<0 g(x)=-2x+2

because we have not told about the description about x so we can put any value in the function.

So the domain is all real numbers.

Now when we take g(x)=2x+2 for x>=0

putting x=0 we get 2 and rest are positive values so the value of g(x) keeps increasing as we increase the value of x. So here range is [2,∞).

Now take g(x)=-2x+2 for x<0

putting smallest number starting from zero but not 0 we will get a number near to 0 but not zero and because when a negative number multiplies with -2 it becomes positive and increase the value of g(x) so here the range becomes (0,∞).

When we talk about overall range it will be [2,∞) ∪(0,∞)

it will be (0,∞).

Hence the domain of the function g(x) is all real numbers and range is from 0 to infinity.

Learn more about domain and range at brainly.com/question/2264373

#SPJ10

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Pilates is a popular set of exercises for the treatment of individuals with lower back pain. The method has six basic principles
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a) We reject H₀     We find difference between the mean of the two groups

b) we accept H₀ : There is no statistical difference  ( in the scale of pain) when the difference in samples means is 1

Step-by-step explanation:

Group 1: Only with educational material

Sample size     n₁  =  42

Sample mean   x₁  =  3,2

Sample standard deviation  s₁  =  2,3

Group 2: With exercises with the treatment of individuals

Sample size    n₂   =  42

Sample mean    x₂  = 5,2  

Sample standard deviation   s₂  = 2,3

Test Hypothesis

Null Hypothesis                     H₀           x₂  -  x₁  = 0  or    x₁  =  x₂

Alternative Hypothesis         Hₐ           x₂  -  x ₁ > 0  or    x₂  >  x₁

Significance level  α  = 0,01

Sample sizes are n₁  =  n₂  >  30

We use z-test

for α  = 0,01     z(c)  ≈  2,32

To calculate z(s)

z(s)  =  (  x₂  -  x₁ ) / √ (2,3)²/42  + (2,3)²/42

z(s)  = ( 5,2  -  3,2 )/ √0,2519

z(s)  =  2 / 0,5

z(s) = 4

Comparing  z(s)  and z(c)

z(s) > z(c)

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b) Does the true average pain level for the control condition exceed that for the treatment condition by more than 1.

In this case

z( s) =  x₂ - x₁ / 0,5

z(s) =  1 /0,5

z(s) = 2

Comparing z(s) and z(c)  now

z(s) < z(c)        2 < 2,32

And z(s) is in the acceptance region ( for the same significance level) and we should accept H₀  equivalent to say that the two groups statistical have the same mean

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