Two ways:
1) guess factors(trial and error)
2) use quadratic formula.
If you use this method then a = -3, b = -6 and c = -1
x = -b +/- [sqrt(b^2 -4ac)/2a]
substituting a, b, and c into our equation we get:
x = - (-6)+/- [sqrt ((-6)^2) - 4(-3)(-1))/2 (-3)]
x = + 6 +/- [sqrt (36 -4 (3)/-6)] if I didnt make a mistake in my signs
x = + 6 +/- [sqrt (36 -12)/-6)]
x = 6 +/- [sqrt (24)/-6] but sqrt 6 x sqrt of 4 = sqrt 24 hence
x = 6 +/- [ sqrt 6 x sqrt 4 /-6] that is:
x = 6 +/- [sqrt 6 x 2 /-6 ]
so x = 6 + [sqrt 6 x 2/-6] and x = 6 - [sqrt 6 x 2/-6]
Answer:
3/4 + 1= 2x - x+1/4
Step-by-step explanation:
Answer:
The correct option is commutative property.
Step-by-step explanation:
The expression that Renee is simplifying is:

It is provided that, Renee recognizes that 7 and
are reciprocals, so she would like to find their product before she multiplies by
.
The associative property of multiplication states that:

The commutative property of multiplication states that:

The distributive property of multiplication states that:

The identity property of multiplication states that:

So, Renee should use the commutative property of multiplication to find the product of 7 and
,

Thus, the correct option is commutative property.
we are given

we can see that
there is no value of x for which g(x) is not defined
so, no vertical asymptote exists
now, we will find horizontal asymptote



so, we get
horizontal asymptote as
............Answer