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iren [92.7K]
3 years ago
11

Among freshman at a certain university, scores on the Math SAT followed the normal curve, with an average of 550 and an SD of 10

0. Fill in the blanks; explain briefly. a) A student who scored 400 on the Math SAT was at the ______ th percentile of the score distribution. b) To be at the 75th percentile of the distribution, a student needed a score of about ______ points on the Math SAT.
Mathematics
1 answer:
lina2011 [118]3 years ago
6 0

Answer:

a) 6.68th percentile

b) 617.5 points

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 550, \sigma = 100

a) A student who scored 400 on the Math SAT was at the ______ th percentile of the score distribution.

Z = \frac{X - \mu}{\sigma}

Z = \frac{400 - 550}{100}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

So this student is in the 6.68th percentile.

b) To be at the 75th percentile of the distribution, a student needed a score of about ______ points on the Math SAT.

He needs a score of X when Z has a pvalue of 0.75. So X when Z = 0.675.

Z = \frac{X - \mu}{\sigma}

0.675 = \frac{X - 550}{100}

X - 550 = 0.675*100

X = 617.5

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Answer:

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Order of Operations: BPEMDAS

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<u>Algebra I</u>

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<u>Algebra II</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

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  2. [Distance] [√Radical] (Parenthesis) Add/Subtract:                                       \displaystyle d = \sqrt{(8)^2+(-4)^2}
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  4. [Distance] [√Radical] Add:                                                                             \displaystyle d = \sqrt{80}
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