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3 years ago

Quadrilieral abcd has a dignosed that are congrount and perpendicular to each other what classification can be given to abcd

Mathematics

1 answer:

olga nikolaevna [1]3 years ago

7 0

Answer:

a kite or a square

Step-by-step explanation:

The fact that the diagonals are congruent is irrelevant, unless you also know something about where they cross each other.

A kite has perpendicular diagonals. If they happen to bisect each other, then the result is a rhombus. If the diagonals are congruent, then that rhombus is a square.

Other ways to get there

A pair of congruent diagonals that cross each other symmetrically will define a trapezoid. If they also bisect each other, the result is a rectangle. If the diagonals of that rectangle are perpendicular, then it is a square.

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The value of the 4 in 34,258 and 47,163

Lera25 [3.4K]

The value of 4 in 34,258 is 10 times the value of the 4 in 47,163.

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4 years ago

Two competitive neighbours build rectangular pools that cover the same area but are different shapes. Pool A has a width of (x +

GenaCL600 [577]

Answer:

a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

b) Area of pool A is equal to area of pool B equal to 24.44 meters.

Solution:

Let’s first calculate area of pool A .

Given that width of the pool A = (x+3)

Length of the pool A is 3 meter longer than its width.

So length of pool A = (x+3) + 3 =(x + 6)

Area of rectangle = length x width

So area of pool A =(x+6) (x+3) ------(1)

Let’s calculate area of pool B

Given that length of pool B is double of width of pool A.

So length of pool B = 2(x+3) =(2x + 6) m

Width of pool B is 4 meter shorter than its length,

So width of pool B = (2x +6 ) – 4 = 2x + 2

Area of rectangle = length x width

So area of pool B =(2x+6)(2x+2) ------(2)

Since area of pool A is equal to area of pool B, so from equation (1) and (2)

(x+6) (x+3) =(2x+6) (2x+2)

On solving above equation for x

(x+6) (x+3) =2(x+3) (2x+2)

x+6 = 4x + 4

x-4x = 4 – 6

x = $\frac{2}{3}$

Dimension of pool A

Length = x+6 = ( $\frac{2}{3}$ ) +6 = 6.667m

Width = x +3 = ( $\frac{2}{3}$ ) +3 = 3.667m

Dimension of pool B

Length = 2x +6 = 2( $\frac{2}{3}$ ) + 6 = $\frac{22}{3}$ = 7.333m

Width = 2x + 2 = 2( $\frac{2}{3}$ ) + 2 = $\frac{10}{3}$ = 3.333m

Verifying the area:

Area of pool A = ( $\frac{20}{3}$ ) x ( $\frac{11}{3}$ ) = $\frac{220}{9}$ = 24.44 meter

Area of pool B = ( $\frac{22}{3}$ ) x ( $\frac{10}{3}$ ) = $\frac{220}{9}$ = 24.44 meter

Summarizing the results:

(a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

(b)Area of pool A is equal to Area of pool B equal to 24.44 meters.

5 0

4 years ago

Factor Polynomial 3y^2+y-14

iris [78.8K]

Answer:

Factored Form: ( y - 2 )( 3y + 7 )

Step-by-step explanation:

1. Let us first write down the problem at hand: 3y^2 + y - 14

2. Now let us break this expression into groups:

3y^2 - 6y + 7y - 14 ⇒ ( 3y^2 - 6y )( 7y - 14 )

3. Factor 3y from 3y^2 - 6y:

3y^2 - 6y ⇒ 3y( y - 2 )

4. Factor 7 from 7y - 14:

7y - 14 ⇒ 7( y - 2 )

5. Substitute Step #3, 4 ⇒ Step #2:

3y( y - 2 ) + 7( y - 2 )

6. Factor common term y - 2:

Answer: ( y - 2 )( 3y + 7 )

4 0

3 years ago

Dara has 12 red couners. She has 7 more red counters than yellow counters. How many yellow counters does dara have ?

morpeh [17]

She has 5 yellow counters

7 0

4 years ago

Read 2 more answers

Latanya and George

tekilochka [14]

Question is Incomplete, Complete question is given below.

Latanya and George are saving up money because they both want to buy new bicycles. Latanya opened a savings account with $50. She just got a job and is determined to save an additional $30 a week. George started a savings account with $75. He is able to save $25 a week. Find the time (in weeks) when Latanya and George will have the same amount of money in their savings accounts.

Answer:

Latanya and George will have same amount after 5 weeks.

Step-by-step explanation:

Given:

Opening Amount in account of Latanya = $50

Amount deposited every week = $30

Let number of week be 'w'.

Total Amount in Latanya savings account will be equal to Opening Amount plus Amount deposited every week multiplied by number of week.

framing in equation form we get;

Total Amount in Latanya savings account = $50+30w$

Also Given:

Opening Amount in account of George = $75

Amount deposited every week = $25

Let number of week be 'w'.

Total Amount in George savings account will be equal to Opening Amount plus Amount deposited every week multiplied by number of week.

framing in equation form we get;

Total Amount in George savings account = $75+25w$

Now we need to number of week when both will have same amount.

Now to find number of week when both will have same amount we need to make both the equation same we get;

$50+30w = 75+25w\\\\30w-25w = 75-50\\\\5w=25\\\\w=\frac{25}{5}=5$

Hence Latanya and George will have same amount after 5 weeks.

8 0

3 years ago