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Phantasy [73]
3 years ago
8

What is the shape of the cross section of the figure that is perpendicular to the rectangular base and passes through the top ve

rtex of the figure?
A rectangular pyramid.
a parallelogram that is not a rectangle
a rectangle
a triangle that must have the same dimensions as one of the faces
a triangle that does not have the same dimensions as one of the faces
Mathematics
2 answers:
photoshop1234 [79]3 years ago
7 0

Answer:

C. a triangle

Step-by-step explanation:

hope this helps c:

lord [1]3 years ago
6 0

Answer:

I think Its D because In the rectangular base its not equal sides like a square so it would be more be like sides that are not perpendicular

Step-by-step explanation:

Im Pretty sure is D

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Option A

If  f(x) = 2x^2 + 1 and g(x) = x^2 - 7 then (f - g)(x) = x^2 + 8

<em><u>Solution:</u></em>

Given that f(x) = 2x^2 + 1 and g(x) = x^2 - 7

To find: (f - g)(x)

We know that,

(f – g)(x) = f (x) - g(x)

Let us substitute the given values of f(x) and g(x) in above formula,

(f - g)(x) = 2x^2 + 1 - (x^2 - 7)

For solving the brackets in above expression,

There are two simple rules to remember:

When you multiply a negative number by a positive number then the product is always negative.

When you multiply two negative numbers or two positive numbers then the product is always positive.

So the expression becomes,

(f - g)(x) = 2x^2 + 1 -x^2 + 7

Combining the like terms,

(f - g)(x) = 2x^2 - x^2 + 1 + 7\\\\(f - g)(x) = x^2 + 8

Thus option A is correct

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