Answer: 1, 7, 1, 7, 1.
Step-by-step explanation:
The given function : and f(1) = 1 for n ≥ 1
We put value of n=1,2,3,4 , we get
For n=1 ,
For n=2 ,
For n=3 ,
For n=4 ,
Hence, the first five terms of the given sequence are 1, 7, 1, 7, 1.
Answer:
Let's complete the square first.
y = x² + 6x + 3
= (x² + 6x + 9) - 6
= (x + 3)² - 6
Therefore, the vertex is (-3, -6) and since the coefficient of (x + 3)² is positive, the vertex is a minimum.
x2+12 (except the 2 in small)
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A
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