Answer:
(1,2)
Step-by-step explanation:
half it! :)
(2, 8) because 8 is not negative
hope it helps,
xXbeautyXx
inferential statistics allows for someone to draw conclusions about a population from the information collected in a population sample.
the qestion is incomplete .please read below to find the missing content
Which of the following allows for someone to draw conclusions about a population from the information collected in a population sample?
a. magnitude statistics
b. central tendency
c. inferential statistics
d. effect size
The population is the number of people living together in a place. The population of a city is the number of people living in that city. These people are called residents or residents. The population includes all individuals living in that particular area.
Population refers to the total number of organisms living in a particular area. Population helps us estimate the number of beings and know how to act accordingly. For example, knowing the exact population of a city allows us to estimate the number of resources required. Similarly, animals can do the same.
Learn more about the population here
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9514 1404 393
Answer:
14.1 years
Step-by-step explanation:
Use the compound interest formula and solve for t. Logarithms are involved.
A = P(1 +r/n)^(nt)
amount when P is invested for t years at annual rate r compounded n times per year.
Using the given values, we have ...
13060 = 8800(1 +0.028/365)^(365t)
13060/8800 = (1 +0.028/365)^(365t) . . . . divide by P=8800
Now we take logarithms to make this a linear equation.
log(13060/8800) = (365t)log(1 +0.028/365)
Dividing by the coefficient of t gives us ...
t = log(13060/8800)/(365·log(1 +0.028/365)) ≈ 0.171461/0.0121598
t ≈ 14.1
It would take about 14.1 years for the value to reach $13,060.
Answer:
Step-by-step explanation:
After every Half life , Half of the mass is left.
After 1st Half life = 100 g / 2 = 50 g
After 2nd Half life = 50 / 2 = 25 g
After 3rd Half life = 25 / 2 = 12.5 g
After 4th Half life = 12.5 / 2 = 6.25 g
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Hope this helped!
<h3>
~AH1807</h3>
