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3 years ago

10

An aquarium in the shape of a rectangular prism has the volume of 3,758.75 cubic inches, length of 24.25 inches, and width of 12

.5 inches. What is the height?
How do I solve this without a calculator?

1 answer:

natulia [17]3 years ago

8 0

You do length times width times you get your area. (I think)

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I need help....Help me please .

maks197457 [2]

Answer:

i cant see the picture

Step-by-step explanation:

5 0

3 years ago

Whats -5n+12n+9+(-3) some one help me with this one

nikdorinn [45]

$-5n+12n+9+(-3)$

$-5n+12n+9-3$

$7n+9-3$

$=7n+6$

Hope this helps!

Thank you for posting your question at here on Brainly.

-Charlie

8 0

3 years ago

If f(x) =x 2 + 10, what is f (-5)?

lisov135 [29]

Answer:

f(-5) = 35

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

<u>Algebra I</u>

Function Notation

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = x² + 10

f(-5) is x = -5

<u>Step 2: Evaluate</u>

Substitute: f(-5) = (-5)² + 10
Exponents: f(-5) = 25 + 10
Add: f(-5) = 35

7 0

3 years ago

write a polynomial function of least degree with integral coefficients that has the given zeros. -(1/3), -i

inessss [21]

Answer:

$f(x)=3x^3+x^2+3x+1$

Step-by-step explanation:

If a real number $-\frac{1}{3}$ is a zero of polynomial function, then

$x-\left(-\dfrac{1}{3}\right)=x+\dfrac{1}{3}$

is the factor of this function.

If a complex number $-i$ is a xero of the polynomial function, then the complex number $i$ is also a zero of this function and

$x-(-i)=x+i\ \text{ and }\ x-i$

are two factors of this function.

So, the function of least degree is

$f(x)=\left(x+\dfrac{1}{3}\right)(x+i)(x-i)=\left(x+\dfrac{1}{3}\right)(x^2-i^2)=\\ \\ =\left(x+\dfrac{1}{3}\right)(x^2+1)=\dfrac{1}{3}(3x+1)(x^2+1)=\dfrac{1}{3}(3x^3+x^2+3x+1)$

If the polynomial function must be with integer coefficients, then it has a form

$f(x)=3x^3+x^2+3x+1$

4 0

4 years ago

What two numbers round to 8.21 when rounded to the nearest hundredth

jeyben [28]

8.213, 8.214 just add 1 hundred to the end

8 0

3 years ago