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2 years ago

Help please come asp

Mathematics

1 answer:

Nastasia [14]2 years ago

7 0

B 6x-18 because when you use the distributive property it is 6x and -18

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What are the first five terms of the sequence defined by the given function?

kenny6666 [7]

Answer: B. -6, -4, -2, 0, 2

Step-by-step explanation: Use the attachment to help you with your answer.

Anyways, have an amazing day!

8 0

2 years ago

Can someone help me im stuck

Tcecarenko [31]

Answer:

(3). 500; (4) 60

Step-by-step explanation:

5 0

2 years ago

Evaluate the following expressions: 1. 5(a+2b)-3b

Alika [10]

Answer:

=5a+7b

Step-by-step explanation:

Expand: 5(a + 2b): 5a + 10b
=5a+10b-3b
Add similar elements: 10b-3b=7b
=5a +7b

4 0

1 year ago

Read 2 more answers

We add the scale factor to each length of an image to get the scaled copy. -True or False?

Anit [1.1K]

Answer:

false

Step-by-step explanation:

A scale drawing is a reduced form in terms of dimensions of an original image / building / object

the scale drawing is usually reduced at a constant dimension

original dimensions / scale of the drawing = dimensions of the scale drawing

To scale an image, divide the original length by the scale

for example the length of the image is 100 and the scale factor is 4

the length of the scale copy = 100/4 = 25

4 0

2 years ago

Find parametric equations for the path of a particle that moves along the circle x2 + (y − 1)2 = 16 in the manner described. (En

ArbitrLikvidat [17]

Answer:

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , c) $x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$ , $y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$ .

Step-by-step explanation:

The equation of the circle is:

$x^{2} + (y-1)^{2} = 16$

After some algebraic and trigonometric handling:

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = 1$

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = \cos^{2} t + \sin^{2} t$

Where:

$\frac{x}{4} = \cos t$

$\frac{y-1}{4} = \sin t$

Finally,

$x = 4\cdot \cos t$

$y = 1 + 4\cdot \sin t$

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

c) $x = 4\cdot \cos t''$ , $y = 1 + 4\cdot \sin t''$

Where:

$4\cdot \cos t' = 0$

$1 + 4\cdot \sin t' = 5$

The solution is $t' = \frac{\pi}{2}$

The parametric equations are:

$x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$

$y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$

7 0

3 years ago