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3 years ago

Convert 3 kilograms to onces

Mathematics

1 answer:

NARA [144]3 years ago

4 0

Answer:

there are 105.82 ounces in 3 kilograms.

Step-by-step explanation:

Hope this helps!

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A large bin of mixed nuts contains peanuts, cashews, almonds, and walnuts. Sheila scoops out a bowl full of nuts and counts how

Zanzabum

Assuming that the ratios stay the same, the answer is going to be 6 because the total number of nuts drawn originally was 48, and 9 were cashews. To maintain this ratio when 32 nuts were drawn, the number of cashews will be 6.

6 0

3 years ago

2(6 − 2x) + 3x = 4 + 2(5 + x) what is x

alexira [117]

First let's get rid of the parenthesis:

12 - 4x + 3x = 4 + 10 + 2x

Now group the x's on the left and the numbers on the right

-4x + 3x - 2x = 4 + 10 - 12

...and simplify

-3x = 2

divide by -3 to isolate x

x = -2/3

5 0

3 years ago

Juliette is making a fruit salad.she purchased 9 2/3 ounces each of 6 different fruits . how many ounces of fruit did she purcha

Anettt [7]

9 2/3 total ounces is a total split up among 6 fruits.

So we need to divide 9 2/3 among the 6 fruits.

= 9 2/3 divide 6

= change 9 2 / 3 in improper fraction
= 9*3 + 2/3

= 29/3 divided by 6/1

= 29/3 x 1/6

= 29/18, change that to mixed fractions.

The answer is 1 11/18 ounces of each fruit.

3 0

3 years ago

This is a polygon with three sides.

poizon [28]

Answer: A three-sided polygon is a triangle.

There are several different types of triangle (see diagram), including: Equilateral – all the sides are equal lengths, and all the internal angles are 60°. Isosceles – has two equal sides, with the third one a different length.

Step-by-step explanation:

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3 years ago

All vectors are in Rn. Check the true statements below:

Oduvanchick [21]

Answer:

A), B) and D) are true

Step-by-step explanation:

A) We can prove it as follows:

$Proy_{cv}y=\frac{(y\cdot cv)}{||cv||^2}cv=\frac{c(y\cdot v)}{c^2||v||^2}cv=\frac{(y\cdot v)}{||v||^2}v=Proy_{v}y$

B) When you compute the product Ax, the i-th component is the matrix of the i-th column of A with x, denote this by Ai x. Then, we have that $||Ax||=\sqrt{(A_1 x)^2+\cdots (A_n x)^2}$ . Now, the colums of A are orthonormal so we have that (Ai x)^2=x_i^2. Then $||Ax||=\sqrt{(x_1)^2+\cdots (x_n)^2}=||x||$ .

C) Consider $S=\{(0,2),(2,0)\}\subseteq \mathbb{R}^2$ . This set is orthogonal because $(0,2)\cdot(2,0)=0(2)+2(0)=0$ , but S is not orthonormal because the norm of (0,2) is 2≠1.

D) Let A be an orthogonal matrix in $\mathbb{R}^n$ . Then the columns of A form an orthonormal set. We have that $A^{-1}=A^t$ . To see this, note than the component $b_{ij}$ of the product $A^t A$ is the dot product of the i-th row of $A^t$ and the jth row of $A$ . But the i-th row of $A^t$ is equal to the i-th column of $A$ . If i≠j, this product is equal to 0 (orthogonality) and if i=j this product is equal to 1 (the columns are unit vectors), then $A^t A=I$

E) Consider S={e_1,0}. S is orthogonal but is not linearly independent, because 0∈S.

In fact, every orthogonal set in R^n without zero vectors is linearly independent. Take a orthogonal set $\{u_1,u_2\cdots u_p\}$ and suppose that there are coefficients a_i such that $a_1u_1+a_2u_2\cdots a_nu_n=0$ . For any i, take the dot product with u_i in both sides of the equation. All product are zero except u_i·u_i=||u_i||. Then $a_i||u_i||=0$ then $a_i=0$ .

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3 years ago