Simplify. wait for photo

I used 8 bags of sand for 12m squared . How much will I need for 15m squared?

vivado [14]

12m divided by 8 bags = 1.5 bags per m

So 1.5 bags times 15m = 22.5 bags o'sand

4 0

3 years ago

Mr. Cole made this diagram of his bedroom. Which is the area of Mr. Cole’s bedroom? 90 square feet 82 square feet 72 square feet

mrs_skeptik [129]

Answer:

The answer is 82 square feet

Step-by-step explanation:

An easy way to do this is to split it into two rectanlges. You can do 10*5 and 8*4 as the dimensions to the two rectangles or you can do 2*4 and 9*8.

I am going to do the first option.

The area of a rectangle is length times width.

Rectangle one can be the one with the dimensions 10 and 5 and the length and width.

Rectangle two can be the one with the dimensions 8 and 4 and the length and width.

Area of rectangle one = 50 feet^2

Area of rectangle two = 32 feet^2

Since we split a large irregular shape into two bits, we must add them together, which results in 82 feet^2.

3 0

2 years ago

Classify the quadrilateral. A. square B. rhombus C. trapezoid D. rectangle also how do you add a picture

igor_vitrenko [27]

Answer:

Hello! Your answer would be, A) Square

Step-by-step explanation:

Hope I helped! Brainiest plz!♥ Have a nice afternoon. Hope you make a 100%! -Amelia

8 0

2 years ago

Please help me with 2b ASAP. Really appreciate it!!

Bogdan [553]

$f(x)=\dfrac{x^2}{x^2+k^2}$

By definition of the derivative,

$f'(x)=\displaystyle\lim_{h\to0}\frac{\frac{(x+h)^2}{(x+h)^2+k^2}-\frac{x^2}{x^2+k^2}}h$

$f'(x)=\displaystyle\lim_{h\to0}\frac{(x+h)^2(x^2+k^2)-x^2((x+h)^2+k^2)}{h(x^2+k^2)((x+h)^2+k^2)}$

$f'(x)=\dfrac{k^2}{x^2+k^2}\displaystyle\lim_{h\to0}\frac{(x+h)^2-x^2}{h((x+h)^2+k^2)}$

$f'(x)=\dfrac{k^2}{x^2+k^2}\displaystyle\lim_{h\to0}\frac{2xh+h^2}{h((x+h)^2+k^2)}$

$f'(x)=\dfrac{k^2}{x^2+k^2}\displaystyle\lim_{h\to0}\frac{2x+h}{(x+h)^2+k^2}$

$f'(x)=\dfrac{2xk^2}{(x^2+k^2)^2}$

$\dfrac{k^2}{(x^2+k^2)^2}$ is positive for all values of $x$ and $k$ . As pointed out, $x\ge0$ , so $f'(x)\ge0$ for all $x\ge0$ . This means the proportion of occupied binding sites is an increasing function of the concentration of oxygen, meaning the presence of more oxygen is consistent with greater availability of binding sites. (The question says as much in the second sentence.)

7 0

3 years ago

How would I solve this equation?

sergiy2304 [10]

Let's solve your equation step-by-step.
2/3(3x+1)=5
Step 1: Simplify both sides of the equation.
2/3(3x+1)=5
Simplify: (Show steps)
2x+2/3=5
Step 2: Subtract 2/3 from both sides.
2x+2/3−2/3=5−2/3
2x=13/3
Step 3: Divide both sides by 2.
2x/2=13/3/2
x=13/6
Answer:
x=13/6

8 0

3 years ago

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