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masya89 [10]
3 years ago
13

Help me with this question

Mathematics
1 answer:
Gala2k [10]3 years ago
8 0
1) This question is asking for the linear equation of the data in the table.
Remember a linear equation in slope-intercept form for this problem is something like a = cm + b, where c = the slope of the equation, b = the y intercept, and m and a are your variables (and values in the table).

This might be confusing if you haven't learned it! Don't worry, all you need to know is the equation and just plug in values to find b (since that's the number that different in all your answer choices).

2) All your answer options have the same slope, c = -4000. All you want to find is the value of b, the y-intercept.
This value you can find by plugging in a set of values from the table into your equation, knowing c = -4000. Let's plug in the first row of values: m = 1, a = 35000.
a = cm + b
a = -4000m + b
35000 = (-4000)(1) + b
35000 = -4000 + b
39000 = b

3) That means b = 39000. Put b = 39000 and c = -4000 together into your equation a = cm + b to get your final equation:
a = cm + b
a = -4000m + 39000

That is answer choice B.

------

Answer: B) -4000m + 39000

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Answer:

12x^2+9x^2-25    (quadratic equation)

a=12, b=9, c=-25

put this in quadratic formula

Step-by-step explanation:

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Compare the two groups of data. Which statement is true?
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Step-by-step explanation:

5x+3x-14=180

8x-14=180

8x=180+14

8x=174

x=174/8

x= 21.75°

if x is 21.75°, then 5x is 108.75°

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4 0
3 years ago
A. The lengths of pregnancies in a small rural village are normally distributed with a mean of 266 days and a standard deviation
Darya [45]

Step-by-step explanation:

a.

mean = 266

sd = 14

cumulative probability = 0.01 so the standard score = -2.33 and 2.33 to the right and left

we find X-upper and X-lower

X-lower = 266-2.33*14 = 233.38

X-upper = 266+2.33*14 = 298.62

Between 233.38 and 298.62

we have sample size = 35

X-lower = 266-2.33*14/√35 = 260.49

X-upper = 266+2.33*14/√35 = 271.5

Between 260.49 and 271.5

b. cumulative probaility = 0.25

standard score = 1.96 to the right and left

x-lower = 6.9-1.96x0.9 = 5.14

x-upper = 6.9+1.96x0.9 = 8.66

Between 5.14 and 8.66

if sample size = 45

x-lower = 6.9-1.96*0.9/√45 = 6.64

x-upper = 6.9+1.96*0.9/√45 = 7.2

Between 6.64 and 7.2

c. standard scores would have cut off value at 0.67 and -0,67

x-lower = 265.3-0.67x15.2 = 255.12

x-upper = 265.3+0.67x15.2 = 275.48

Between 255.12 and 275.48

d. we will have critical values at 1.00 and -1.00

X-lower = 265-1x16 = 249

x-upper = 265+1x16 = 281

Between 249 and 281

with sample size = 44

x-lower = 265-1x16/√44 = 262.59

x-upper = 265+1x16/√44 = 267.41

Between 262.59 and 267.41

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