3 years ago

Name the place value to which each number was rounded 0.982to 0.98

1 answer:

8 0

The Hundredths place because 2 is in the thousandths place. 5 or more change the score, 4 or less let it rest. 8 remained the same because 2 is less than 4.

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Factor of 4-(2a+3b)^2

Anna71 [15]

$4-(2a+3b)^2$

$(2a+3b)^2 :$

$4a^2+12ab+9b^2$

$= 4-(4a^3+12ab+9b^2)$

$=-(4a^2)-(12ab)-(9b^2)$

apply minus - plus rules :

$+(-a)=-a$

Refine:

$=-4-4a^2-12ab-9b^2$

<span>hope this helps!</span>

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3 years ago

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3 years ago

Free brainliest! to first answer!

Dmitry [639]

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