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oksano4ka [1.4K]
3 years ago
14

Work out the surface area of this cylinder.with radius 2 cmand height 4 cm​

Mathematics
1 answer:
Tju [1.3M]3 years ago
3 0

Answer:

75.39cm ^{2}

Step-by-step explanation:

area = 2\pi \times r \times h  + 2\pi \times  {r}^{2}  \\ = 2 \times \pi \times 2 \times 4 + 2 \times \pi \times 22 \\  = 75.39822cm ^{2}

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Answer:

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Step-by-step explanation:

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3 years ago
Write the equation of a line in slope-intercept form that passes through the point (0,-7) and has a slope of 3/4.
kondor19780726 [428]

Answer:

y=3/4x-7

Step-by-step explanation:

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2 years ago
If α and β are the zeros of the quadratic polynomial f(x) = 3x2–4x + 5, find a polynomialwhose zeros are 2α + 3β and 3α + 2β.
Lelechka [254]

Answer:

\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }

Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

f(x)=3(x^2-\dfrac{4}{3}x+\dfrac{5}{3}) = 3(x-a)(x-b)=3(x-(a+b)x+ab)

So we can say that

a+b=\dfrac{4}{3}\\ab=\dfrac{5}{3}

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab

and we can notice that

a^2+b^2=(a+b)^2-2ab so

(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab

it comes

x^2-5*\dfrac{4}{3}x+6(\dfrac{4}{3})^2+\dfrac{5}{3}

multiply by 3

3x^2-20x+2*16+5=3x^2-20x+37

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