What is the image of point (-1,-2) if the rotation is 90 degrees

Which of the graphs below correctly solves for x in the equation −x2 − 3x − 1 = −x − 4?

Tanzania [10]

We have
−x²<span> − 3x − 1 = −x − 4

let
f(x)=</span>−x² − 3x − 1
g(x)= −x − 4
the solution for
f(x)=g(x) is the intersection both graphs

using a graph tool
see the attached figure

the solution are the points
(-3,-1)
and
(1,-5)

8 0

4 years ago

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Write a story or situation that can be represented by the given equation.<br><br> 4a+5=12a−11

Leto [7]

Answer:

a = 4

Step-by-step explanation:

STEP 1) 4a - 16 = 4 • (a - 4)

3 0

3 years ago

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The table below shows all of the possible outcomes of rolling a six-sided number cube and flipping a coin.

exis [7]

maybe bc of how many times you can add the number itself

3 0

3 years ago

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The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.917 g and a standard deviation

Nutka1998 [239]

Answer:

$z = \frac{0.872-0.917}{\frac{0.303}{\sqrt{37}}}= -0.903$

And we can find this probability to find the answer:

$P(z$

And using the normal standar table or excel we got:

$P(z$

Step-by-step explanation:

Let X the random variable that represent the amounts of nocatine of a population, and for this case we know the distribution for X is given by:

$X \sim N(0.917,0.303)$

Where $\mu=0.917$ and $\sigma=0.303$

We have the following info from a sample of n =37:

$\bar X= 0.872$ the sample mean

And we want to find the following probability:

$P(\bar X \leq 0.872)$

And we can use the z score formula given by;

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for the value of 0.872 we got:

$z = \frac{0.872-0.917}{\frac{0.303}{\sqrt{37}}}= -0.903$

And we can find this probability to find the answer:

$P(z$

And using the normal standar table or excel we got:

$P(z$

6 0

3 years ago

Find the value of the variable.

nalin [4]

Answer:

The variable, y is 11°

Step-by-step explanation:

The given parameters are;

in triangle ΔABC; ${}$ in triangle ΔFGH;

Segment $\overline {AB}$ = 14 ${}$ Segment $\overline {FG}$ = 14

Segment $\overline {BC}$ = 27 ${}$ Segment $\overline {GH}$ = 19

Segment $\overline {AC}$ = 19 ${}$ Segment $\overline {FH}$ = 2·y + 5

∡A = 32° ${}$ ∡G = 32°

∡A = ∠BAC which is the angle formed by segments $\overline {AB}$ = 14 and $\overline {AC}$ = 19

Therefore, segment $\overline {BC}$ = 27, is the segment opposite to ∡A = 32°

Similarly, ∡G = ∠FGH which is the angle formed by segments $\overline {FG}$ = 14 and $\overline {GH}$ = 19

Therefore, segment $\overline {FH}$ = 2·y + 5, is the segment opposite to ∡A = 32° and triangle ΔABC ≅ ΔFGH by Side-Angle-Side congruency rule which gives;

$\overline {FH}$ ≅ $\overline {BC}$ by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

∴ $\overline {FH}$ = $\overline {BC}$ = 27° y definition of congruency

$\overline {FH}$ = 2·y + 5 = 27° by transitive property

∴ 2·y + 5 = 27°

2·y = 27° - 5° = 22°

y = 22°/2 = 11°

The variable, y = 11°

8 0

3 years ago