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s2008m [1.1K]
3 years ago
7

What is the image of point (-1,-2) if the rotation is 90 degrees

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
5 0
(1,-2)...............
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Which of the graphs below correctly solves for x in the equation −x2 − 3x − 1 = −x − 4?
Tanzania [10]
We have 
−x²<span> − 3x − 1 = −x − 4

let 
f(x)=</span>−x² − 3x − 1
g(x)= −x − 4
the solution for
f(x)=g(x) is the intersection both graphs

using a graph tool
see the attached figure

the solution are the points
(-3,-1)
and
(1,-5)

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4 years ago
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Write a story or situation that can be represented by the given equation.<br><br> 4a+5=12a−11
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Answer:

          a = 4

Step-by-step explanation:

STEP 1)  4a - 16  =   4 • (a - 4)

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3 years ago
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The table below shows all of the possible outcomes of rolling a six-sided number cube and flipping a coin.
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maybe bc of how many times you can add the number itself

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The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.917 g and a standard deviation
Nutka1998 [239]

Answer:

z = \frac{0.872-0.917}{\frac{0.303}{\sqrt{37}}}= -0.903

And we can find this probability to find the answer:

P(z

And using the normal standar table or excel we got:

P(z

Step-by-step explanation:

Let X the random variable that represent the amounts of nocatine of a population, and for this case we know the distribution for X is given by:

X \sim N(0.917,0.303)  

Where \mu=0.917 and \sigma=0.303

We have the following info from a sample of n =37:

\bar X= 0.872 the sample mean

And we want to find the following probability:

P(\bar X \leq 0.872)

And we can use the z score formula given by;

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for the value of 0.872 we got:

z = \frac{0.872-0.917}{\frac{0.303}{\sqrt{37}}}= -0.903

And we can find this probability to find the answer:

P(z

And using the normal standar table or excel we got:

P(z

6 0
3 years ago
Find the value of the variable.
nalin [4]

Answer:

The variable, y is 11°

Step-by-step explanation:

The given parameters are;

in triangle ΔABC;          {}              in triangle ΔFGH;

Segment \overline {AB} = 14         {}               Segment \overline {FG} = 14

Segment \overline {BC} = 27         {}              Segment \overline {GH} = 19

Segment \overline {AC} = 19         {}               Segment \overline {FH} = 2·y + 5

∡A = 32°                       {}                ∡G = 32°

∡A = ∠BAC which is the angle formed by segments \overline {AB} = 14 and \overline {AC} = 19

Therefore, segment \overline {BC} = 27, is the segment opposite to ∡A = 32°

Similarly, ∡G = ∠FGH which is the angle formed by segments \overline {FG} = 14 and \overline {GH} = 19

Therefore, segment \overline {FH} = 2·y + 5, is the segment opposite to ∡A = 32° and triangle ΔABC ≅ ΔFGH by Side-Angle-Side congruency rule which gives;

\overline {FH} ≅ \overline {BC} by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

∴ \overline {FH} = \overline {BC} = 27° y definition of congruency

\overline {FH} = 2·y + 5 = 27° by transitive property

∴ 2·y + 5 = 27°

2·y = 27° - 5° = 22°

y = 22°/2 = 11°

The variable, y = 11°

8 0
3 years ago
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