So both the rabbits are Bb which means there will be a chart which comes out with one BB, Two Bb and one bb, For the rabbit to become brown fur it would need to get bb from theirs parents reproducing, if it's Bb they will just carry the trait recessive trait again and if it's BB they won't be carrying the trait
Commensalism :)
in case when bacteria and human, both are benifited.
Answer:
0%
Explanation:
Achondroplasia is an autosomal dominant disorder that is expressed in both homozygous and heterozygous dominant genotypes. Since two affected parents have a normal girl child, both the parents should be heterozygous carrier for the disease. Let's assume that the dominant allele "A" is responsible for the disease. Genotype of both the parents of the girl would be "Aa". The genotype of girl with normal stature is "aa". Genotype of her normal partner is "aa".
A cross betwee aa X aa would get all the progeny with "aa" genotype. Therefore, all of their children would have normal stature and there is 0% probability for them to have a child with achondroplasia.
Answer:
Approximately 7%
Explanation:
I found this answer in an article from around 2015 so it should probably be higher since the demand for large animal vets is higher currently