Question

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Answer 1

Answer:  C) 3 real zeros & 2 imaginary zeros

Step-by-step explanation:

Since the function has a degree of 5, then there must be 5 zeros.  

If each of the 3 given zeros crosses the x- axis (which is what happens when it has an odd-numbered multiplicity), then there are 2 zeros missing.

The missing zeros are imaginary.

(3 zeroes × multiplicity of 1) + (2 imaginary)

                  3                         +          2           = 5  $\large\checkmark$

Answer 2

The answer is C: Three real zeros and 2 imaginary zeros