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igomit [66]
4 years ago
15

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Mathematics
2 answers:
Monica [59]4 years ago
5 0

Answer:  C) 3 real zeros & 2 imaginary zeros

<u>Step-by-step explanation:</u>

Since the function has a degree of 5, then there must be 5 zeros.  

If each of the 3 given zeros crosses the x- axis (which is what happens when it has an odd-numbered multiplicity), then there are 2 zeros missing.

The missing zeros are imaginary.

(3 zeroes × multiplicity of 1) + (2 imaginary)

                  3                         +          2           = 5  \large\checkmark

Nutka1998 [239]4 years ago
4 0

The answer is C: Three real zeros and 2 imaginary zeros

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