4 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Mathematics

2 answers:

Monica [59]4 years ago

5 0

Answer: C) 3 real zeros & 2 imaginary zeros

<u>Step-by-step explanation:</u>

Since the function has a degree of 5, then there must be 5 zeros.

If each of the 3 given zeros crosses the x- axis (which is what happens when it has an odd-numbered multiplicity), then there are 2 zeros missing.

The missing zeros are imaginary.

(3 zeroes × multiplicity of 1) + (2 imaginary)

3 + 2 = 5 $\large\checkmark$

Nutka1998 [239]4 years ago

4 0

The answer is C: Three real zeros and 2 imaginary zeros

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