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kenny6666 [7]
3 years ago
7

the length of a rectangle is 8in. more than it’s width. the perimeter of the rectangle is 24in. what are the width and length of

the rectangle?
Mathematics
1 answer:
igomit [66]3 years ago
4 0
The width is 2 in., and the with is 8 in.
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Please help ME ASAP!!Please explain the answer
Fynjy0 [20]

Answer:

It seems like you misunderstood the instructions, though I don't blame you because they wrote it strangely. I believe that you're supposed to draw your own conclusion and then explain how you go there, rather than analyze a conclusion that was already drawn for you. If a long drive=a large fare, and you've been told that the driver has a long drive, you can draw the conclusion that "The fare will be large."

5 0
3 years ago
What is the length of ST?
adell [148]
Hi there!

Since ST is a tangent to the circle, we can use the relationship: tangent squared = external secant segment x entire secant segment.

WORK:
(I will be using x in place of ST)
x^2 = 7(23 + 7)
x^2 = 7(30)
x^2 = 210
x = squareroot(210) or approximately 14.5 inches

Hope this helps!! :)
4 0
3 years ago
Can anyone help me solve a trigonomic identity problem and also help me how to do it step by step?
dusya [7]
\bf cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}
\qquad csc(\theta)=\cfrac{1}{sin(\theta)}
\\\\\\
sin^2(\theta)+cos^2(\theta)=1\\\\
-------------------------------\\\\

\bf \cfrac{cos(\theta )cot(\theta )}{1-sin(\theta )}-1=csc(\theta )\\\\
-------------------------------\\\\
\cfrac{cos(\theta )\cdot \frac{cos(\theta )}{sin(\theta )}}{1-sin(\theta )}-1\implies \cfrac{\frac{cos^2(\theta )}{sin(\theta )}}{\frac{1-sin(\theta )}{1}}-1\implies 
\cfrac{cos^2(\theta )}{sin(\theta )}\cdot \cfrac{1}{1-sin(\theta )}-1
\\\\\\
\cfrac{cos^2(\theta )}{sin(\theta )[1-sin(\theta )]}-1\implies 
\cfrac{cos^2(\theta )-1[sin(\theta )[1-sin(\theta )]]}{sin(\theta )[1-sin(\theta )]}

\bf \cfrac{cos^2(\theta )-1[sin(\theta )-sin^2(\theta )]}{sin(\theta )[1-sin(\theta )]}\implies \cfrac{cos^2(\theta )-sin(\theta )+sin^2(\theta )}{sin(\theta )[1-sin(\theta )]}
\\\\\\
\cfrac{cos^2(\theta )+sin^2(\theta )-sin(\theta )}{sin(\theta )[1-sin(\theta )]}\implies \cfrac{\underline{1-sin(\theta )}}{sin(\theta )\underline{[1-sin(\theta )]}}
\\\\\\
\cfrac{1}{sin(\theta )}\implies csc(\theta )
7 0
3 years ago
An instructor asked her students how much time (to the nearest hour) they spent studying for the midterm. The data are displayed
BARSIC [14]

Based on the data displayed in the histogram, the percentage of students who study 2 or more hours for the midterm is 88%.

<h3>What percentage study 2 hours or more?</h3>

First, find the number of students studying:

= 3 + 9 + 6 + 3 + 2 + 1 + 1

= 25

The number of students studying 2 or more hours for the exam are:

= 9 + 6 + 3 + 2 + 1 + 1

= 22 students

The percentage studying for two hours or more is:

= 22 / 25

= 88%

Find out more on percentages at brainly.com/question/25567167.

#SPJ1

8 0
2 years ago
On a cruise, 80% of the passengers are staying in "economy" rooms. If there are 320 passengers in "economy rooms, how many total
stealth61 [152]
I think that the answer is 550 people on the cruise. i used my math notes
5 0
3 years ago
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