Question

In ΔOPQ, the measure of ∠Q=90°, PQ = 3.6 feet, and OP = 9.1 feet. Find the measure of ∠P to the nearest tenth of a degree.

Answer 1

Step-by-step explanation:

$\because \cos \: \angle P = \frac{PQ}{OP} \\ \\ \therefore \: \cos \: \angle P = \frac{3.6}{9.1} \\ \\ \therefore \: \cos \: \angle P = 0.3956 \\ \\ \therefore \: \cos \: \angle P = \cos \: 66.6966 \\ \\ \huge \red{ \boxed{\therefore \: \angle P = 66.7 \degree}}$