Answer:
The answer to your question is: 9.81 x 10⁻⁵ (third option)
Step-by-step explanation:
0.0000981 Just move the point 5 places to the right.
9.81 Express the result as x 10
and the power will be the number of places
you move the point with negative sign
9.81 x 10⁻⁵
There is no picture below lol
Answer:
<h2>if the sum of the two angles is 90°,then they are said to be <u>complementary angles.</u></h2>
By using what we know about intersecting lines, we will see that:
- a) ∡7 = 47°
- b) 47° + (2x - 5)° = 180°
- c) x = 69
<h3>
How to get the measures of the angles for two intersecting lines?</h3>
When two lines intersect, 4 angles are formed. There are two properties that these angles have.
- If the angles are adjacent, then their measures add up to 180°
- If the angles are not adjacent, these angles have the same measure.
a) We know that ∡5 = 47°
And 7 is not adjacent to 5, then 7 has the same measure:
∡7 = 47°
b) 6 and 5 are adjacent, then we must have that:
∡5 + ∡6 = 180°
47° + (2x - 5)° = 180°
That is the equation we need to solve to get the value of x.
c) To solve the linear equation we need to isolate x, let's do that:
47° + (2x - 5)° = 180°
(2x - 5)° = 180° - 47° = 133°
2x - 5 = 133
2x = 133 + 5 = 138
x = 138/2 = 69.
If you want to learn more about linear equations, you can read:
brainly.com/question/1884491
Solution:
Given the triangle ABC as shown below:
To draw the image,
step 1: Determine the coordinates of the vertices of the triangle.
In the above graph,
![\begin{gathered} A(6,7) \\ B(9,9) \\ C(8,6) \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20A%286%2C7%29%20%5C%5C%20B%289%2C9%29%20%5C%5C%20C%288%2C6%29%20%5Cend%7Bgathered%7D)
step 2: Evaluate the new coordinates A'B'C' of the triangle after a dilation centered at the origin with a scale factor of 2.
After a dilation centered at the origin with a scale factor of 2, the iniatial coordinates of the vertices of the triangle are multiplid by 2.
Thus,
![\begin{gathered} A(6,7)\to A^{\prime}(12,14) \\ B(9,9)\to B^{\prime}(18,18) \\ C(8,6)\to C^{\prime}(16,12) \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20A%286%2C7%29%5Cto%20A%5E%7B%5Cprime%7D%2812%2C14%29%20%5C%5C%20B%289%2C9%29%5Cto%20B%5E%7B%5Cprime%7D%2818%2C18%29%20%5C%5C%20C%288%2C6%29%5Cto%20C%5E%7B%5Cprime%7D%2816%2C12%29%20%5Cend%7Bgathered%7D)
step 3: Draw the triangle A'B'C'.
The image of the triangle A'B'C' is as shown below: