The sum of 18 and a number

Mathematics

2 answers:

Kryger [21]3 years ago

6 0

Answer:

The expression you are looking for is: 18+x

Step-by-step explanation:

quester [9]3 years ago

4 0

18+ x the variable

That’s what your looking for

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How to solve this? Is the question correct? ty :)

bezimeni [28]

Answer:

The proposition is true.

Step-by-step explanation:

Now we proceed to demostrate that expression given is true by algebraic means:

1) $\frac{x^{-1}+y^{-1}}{x^{-1}}+\frac{x^{-1}-y^{-1} }{y^{-1}}$ Given

2) $\frac{y^{-1}\cdot (x^{-1}+y^{-1})+x^{-1}\cdot (x^{-1}-y^{-1})}{x^{-1}\cdot y^{-1}}$ $\frac{a}{b} + \frac{c}{d} = \frac{a\cdot d+b\cdot c}{b\cdot d}$

3) $\frac{x^{-1}\cdot y^{-1}+y^{-2}+x^{-2}-x^{-1}\cdot y^{-1}}{x^{-1}\cdot y^{-1}}$ Distributive property/ $a^{b}\cdot a^{c} = a^{b+c}$

4) $\frac{x^{-2}+y^{-2}}{(x\cdot y)^{-1}}$ Commutative, associative and modulative properties/Existence of additive inverse/ $a^{b}\cdot c^{b} = (a\cdot c)^{b}$

5) $[(x\cdot y)^{-1}]^{-1}\cdot (x^{-2}+y^{-2})$ Commutative property/Definition of division

6) $(x\cdot y)\cdot (x^{-2}+y^{-2})$ $(x^{-1})^{-1}$

7) $x^{-1}\cdot y + x\cdot y^{-1}$ Distributive property/Associative property/ $a^{b}\cdot a^{c} = a^{b+c}$

8) $(x^{-1}\cdot y^{-1})\cdot y^{2} + (x^{-1}\cdot y^{-1})\cdot x^{2}$ Modulative property/Existence of additive inverse/ $a^{b}\cdot a^{c} = a^{b+c}$