1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sindrei [870]
3 years ago
15

Do same-side interior angles have to be on the same (in this case) horizontal line?

Mathematics
1 answer:
Shtirlitz [24]3 years ago
7 0
I believe it can be AD, since B and D are equal to each other.
You might be interested in
A person jogged 10 times along the perimeter of a rectangular field at the rate of 12 kilometers per hour for 30 minutes. If fie
balu736 [363]

Answer:

20,000m²

Step-by-step explanation:

If they jog 12 km/h for half an hour, they have covered.

12 X 0.5 = 6km in 10 circuits. Making 1 perimeter

6 / 10 =0.6 km (600 m).

To determine area we need to convert this perimeter to length and width. We know that it is a rectangle, with 2 equal widths and 2 equal lengths, and the length is twice the width.

So L = 2W

Perimeter = 2W + 2L

600 m = 2W + 2(2W)

600 m = 6W

W = 100 m

L = 200 m

Area = 100 X 200 = 20,000 m²

4 0
3 years ago
Your parents took your family out to dinner . Your parents wanted to give the waiter a 15% tip. If the total amount of the dinne
marysya [2.9K]

15% = 0.15

multiply the bill ( 42.00) by 0.15 for the amount of tip

42.00 * 0.15 = 6.30

 the tip = $6.30

8 0
3 years ago
Read 2 more answers
2 1/2 divided by -1 1/3
11111nata11111 [884]

Answer:

The answer is -1.879699

6 0
4 years ago
A) If a:b = 2:5 and b:c = 3:4, find (i) a:c(ii) a:b:c
kobusy [5.1K]

Answer:

A i. a:c=3:10

ii. a:b:c=2:5:10

B i. x:z=2:5

ii. x:y:z=2:4:5

Step-by-step explanation:

A.) If a:b = 2:5 and b:c = 3:4, find (i) a:c(ii) a:b:c

a:b=a/b=2/5

b:c=b/c=3/4

a/b*b/c=a/c

2/5*3/4=a/c

6/20=a/c

3/10=a/c

Therefore, a:c=3:10

a:b:c

a:b=2:5

b:c=3:4

b is common to both ratios

The value of b in the first ratio is 5 and b is 3 in the second ratio

Lets take the LCM of both values

LCM of 5 and 3=15

So, we will change the value of b in the first ratio and second ratio to 15

By doing this, we will multiply the whole first ratio by 3

We have, 6:15

We multiply the whole second ratio by 5

We have, 15:20

Therefore a:b:c=6:15:20

=2:5:10

B. If x:y = 1:2 and y:z = 4:5,

x:y=x/y=1:2

y:z=y/z=4:5

x/y*y/z=x/z

1/2*4/5=x/z

4/10=x/z

2/5=x/z

Therefore, x:z=2:5

x:y:z

x:y=1:2

y:z=4:5

y is common to both ratio

Take the LCM of y values in both ratio

LCM of 2 and 4 =4

So,we will change the value of y in the first and second ratio to 4

By doing this, we will multiply the whole first ratio by 2

We have, 2:4

We will also multiply the whole second ratio by 1

We have, 4:5

Therefore, x:y:z=2:4:5

8 0
3 years ago
What multiplies to 6 and adds to -7
____ [38]
-1*-6=6
-1+(-6)=-7

Hope that helped
7 0
3 years ago
Other questions:
  • Tomas learned that the product of the polynomials (a + b)(a2 – ab + b2) was a special pattern that would result in a sum of cube
    13·2 answers
  • ASAP PLEASE PLEASE IM BEING TIMED ASAP PLEASE
    15·2 answers
  • The area of a rectangle is 28^2 , and the length of the rectangle is 1ft more than double the width. find the dimensions of the
    12·1 answer
  • This is dealing with special triangles
    15·1 answer
  • A rectangular floor is 7 yards long and 3 yards wide. What is the area of the floor in square feet?
    12·2 answers
  • Kalon and his friend Marna own a chimney sweep service company. Working together, they can clean a chimney in 1 5/7 hours. If it
    7·1 answer
  • If the mean of 2 3 x and 5 is 4,find x​
    14·1 answer
  • Help me solve this problem please
    12·1 answer
  • 12-inch board is to be cut into three pieces so that the second piece is twice as long as the first piece and the third piece is
    12·1 answer
  • Create the equation of a circle that has a center at (1,3) and a radius of 4 units.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!