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lara31 [8.8K]
3 years ago
12

Help me solve this problem please

Mathematics
1 answer:
aleksklad [387]3 years ago
8 0

Answer:

(2,5) is right answer ok

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a. 47.6mph (distance divided by time = speed. divide each rowers distance by their speed, then add them all)

b. 1.26 minutes per mile (i used a calculator so i dunno how to explain)

let me know if this is right or not :)

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Mack the bug starts at (0,0) at noon and each minute moves one unit right or one unit up. He is trying to get to the point (5,7)
PSYCHO15rus [73]
<span>This is a very nice counting question. Suggestion / Hint: Count how many ways he can get from (0,0) to (5,7) by going through the point (2,3). Then subtract that from ALL POSSIBLE ways he can get from (0,0) to (5,7). Hint for the hint: How many ways he can get from (0,0) to (5,7) by going through the point (2,3)? Well, that's the SUM of how many ways he can get from (0,0) to (2,3) and how many ways he get get from (2,3) to (5,7). Hope this helps! :)</span>
4 0
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You invest $300 at 4% interest, compounded every year. What will your balance be after 5 years? (Remember, the formula is A = P(
Stells [14]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill\\ P=\textit{original amount deposited}\to &\$300\\ r=rate\to 4\%\to \frac{4}{100}\to &0.04\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{every year, once} \end{array}\to &1\\ t=years\to &5 \end{cases} \\\\\\ A=300\left(1+\frac{0.04}{1}\right)^{1\cdot 5}\implies A=300(1.04)^5\implies A\approx 364.996

3 0
3 years ago
The data represents the number of runs allowed by 8 college softball pitchers. {18, 49, 38, 41, 33, 44, 42, 22}
lawyer [7]

This Question is incomplete

Complete Question:

The data represents the number of runs allowed by 8 college softball pitchers. {18, 49, 38, 41, 33, 44, 42, 22}

What is the five number summary:

a) Minimum

b) Q₁

c) Median

d) Q₃

e) Maximum

Answer:

a) Minimum = 18

b) Q₁ = 27.5

c) Median = 39.5

d) Q₃ = 43

e) Maximum = 49

Step-by-step explanation:

From the above diagram, we were given the following set of data.

{18, 49, 38, 41, 33, 44, 42, 22}

Before answering any of the questions, we have to rearrange the data from the lowest to the highest (ascending order). Hence, we have:

{18, 22, 33, 38, 41, 42, 44, 49}

a) Minimum

{18, 22, 33, 38, 41, 42, 44, 49}

Looking at this set of arranged data, the minimum number is the least or lowest number.

This number is 18

b) Q₁

{18, 22, 33, 38, 41, 42, 44, 49}

Q₁ means First Quartile. The formula is = ¼(n + 1)th value

n = Number of terms in the data set = 8

= ¼(8 + 1)th value

= ¼(9)th value

= 2 1/4 value

= 2.25 value

In the above Question, the 2.25 value is the value between the second and third number.

Hence:

22+33/2 = 55/2 = 27.5

Therefore, Q₁ = 27.5

c) Median

{18, 22, 33, 38, 41, 42, 44, 49}

The median of the number is the number in the middle

For this data, we have 8 number, Hence the median is the sum of the 4th and 5th term divided by 2

4th term = 38

5th term = 41

= 38 + 41/ 2 = 79/2

= 39.5

Hence, the median = 39.5

d) Q₃

{18, 22, 33, 38, 41, 42, 44, 49}

Q₃ means Third Quartile. The formula is = ¾(n + 1)th value

n = Number of terms in the data set = 8

= ¾(8 + 1)th value

= ¾(9)th value

= 6 3/4 value

= 6.75 value

In the above Question, the 6.75 value is the value between the sixth and seventh number.

Hence:

42+44/2 = 86/2 = 43

Therefore, Q₃ = 43

e) Maximum

{18, 22, 33, 38, 41, 42, 44, 49}

Looking at this set of arranged data, the Maximum number is the highest number.

This number is 49

6 0
3 years ago
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