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Fittoniya [83]
3 years ago
14

Graph the integer -3 and its opposite on the number line

Mathematics
2 answers:
Harlamova29_29 [7]3 years ago
6 0
Free pofree pointsfree pointsfree pointsfree pointsfree pointsfree pointsfree free pointsfree pointsfree pointsfree pointsfree pointsfree pointsfree pointspointsree pointsfree pointsfree pointsints
wel3 years ago
5 0

Answer:

yes

Step-by-step explanation:

reeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

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Answer:

The answer is 80%

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2 years ago
Ursula tosses two six-sided number cubes and MULTIPLIES the numbers rolled. Which of these is a list of the outcomes of the two
Black_prince [1.1K]

Answer:

3,4,5,6,7,8

Step-by-step explanation:

sum of 2 with other possible numbers:

2+1, 2+2, 2+3, 2+4, 2+5, 2+6

3, 4, 5, 6, 7, 8

5 0
3 years ago
2 + 3 + 8 + 1 + 9 + 10 - 11 +10 = ?
Illusion [34]
The answer is 32 ………………..
7 0
2 years ago
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Area of a triangle with points at (-9,5), (6,10), and (2,-10)
Ann [662]
First we are going to draw the triangle using the given coordinates. 
Next, we are going to use the distance formula to find the sides of our triangle.
Distance formula: d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Distance from point A to point B:
d_{AB}= \sqrt{[6-(-9)]^2+(10-5)^2}
d_{AB}= \sqrt{(6+9)^2+(10-5)^2}
d_{AB}= \sqrt{(15)^2+(5)^2}
d_{AB}= \sqrt{225+25}
d_{AB}= \sqrt{250}
d_{AB}=15.81

Distance from point A to point C:
d_{AC}= \sqrt{[2-(-9)]^2+(-10-5)^2}
d_{AC}= \sqrt{(2+9)^2+(-10-5)^2}
d_{AC}= \sqrt{11^2+(-15)^2}
d_{AC}= \sqrt{121+225}
d_{AC}= \sqrt{346}
d_{AC}= 18.60

Distance from point B from point C
d_{BC}= \sqrt{(2-6)^2+(-10-10)^2}
d_{BC}= \sqrt{(-4)^2+(-20)^2}
d_{BC}= \sqrt{16+400}
d_{BC}= \sqrt{416}
d_{BC}=20.40

Now, we are going to find the semi-perimeter of our triangle using the semi-perimeter formula:
s= \frac{AB+AC+BC}{2}
s= \frac{15.81+18.60+20.40}{2}
s= \frac{54.81}{2}
s=27.41

Finally, to find the area of our triangle, we are going to use Heron's formula:
A= \sqrt{s(s-AB)(s-AC)(s-BC)}
A=\sqrt{27.41(27.41-15.81)(27.41-18.60)(27.41-20.40)}
A= \sqrt{27.41(11.6)(8.81)(7.01)}
A=140.13

We can conclude that the perimeter of our triangle is 140.13 square units.

3 0
2 years ago
What is the value of x in the equation 2x - 3 = 9- 4x? o 6 o 3 O 1 02​
riadik2000 [5.3K]

Answer:

2? The last one

Step-by-step explanation:

6 0
2 years ago
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