3 years ago

A suit is on sale for $120. this is 4/5 of the regular price. what is the regular price of the suit

1 answer:

4 0

The 120$ is 4/5 of its regual price (x)

so :

4/5 of x = 120

i.e: 4x/5 = 120

Solve for x:

x = 120*5/4 = 150$

That was its regular price.

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3 years ago

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tamaranim1 [39]

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3 years ago

WILL GIVE BRAINLIEST, THANKS, AND 5 STARS! PLEASE HELP ME!

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Answer:

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Step-by-step explanation:

Method 1

Apply Difference of Two Squares Formula: $a^2-b^2=(a+b)(a-b)$

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$\implies b=\sqrt{4^2} =4$

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$\implies (x+4)(x-4)=0$

$\implies (x+4)=0 \implies x=-4$

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Method 2

Given equation:

$x^2-16=0$

Add 16 to both sides:

$\implies x^2-16+16=0 + 16$

$\implies x^2=16$

Square root both sides:

$\implies \sqrt{x^2}=\sqrt{16}$

$\implies x=\pm4$

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