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vredina [299]
3 years ago
11

Use the substitution method to solve the system of equations. Choose the

Mathematics
1 answer:
bixtya [17]3 years ago
4 0

Answer:

C

Step-by-step explanation:

Given the 2 equations

2x - y = 10 → (1)

2x - 2y = 4 → (2)

Rearrange (2) expressing 2x in terms of y by adding 2y to both sides

2x = 4 + 2y

Substitute 2x = 4 + 2y into (1)

4 + 2y - y = 10, that is

4 + y = 10 ( subtract 4 from both sides )

y = 6

Substitute y = 6 into either of the 2 equations and solve for x

Using (1)

2x - 6 = 10 ( add 6 to both sides )

2x = 16 ( divide both sides by 2 )

x = 8

Solution is (8, 6 ) → C

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3.14/5.71=0.18330414466 years hope this hepls
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A bin contains seven red chips, nine green chips, three yellow chips, and six blue chips. Find the probability of drawing a yell
igomit [66]

Answer:

a) 3/100

Step-by-step explanation:

There are 25 total chips

P(Yellow) = 3/25

With no replacement P(Blue) = 6/24 = 1/4

Multiply 3/25* 1/4= 3/100

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The Gwinnett fair is in town!! You and your friends decided to meet at the fair this weekend. You have earned $50 from math tuto
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Step-by-step explanation:

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3 years ago
Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
3 years ago
A meter stick perpendicular to the ground casts a 1.5 meter shadow at the same time a telephone pole casts a shadow that is 9 me
snow_lady [41]
The height of the telephone pole = 9 / 1.5 = 6 meters
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