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Blababa [14]
3 years ago
12

X+9/x^3-9x^2+15x+25 how do I solve this

Mathematics
1 answer:
mezya [45]3 years ago
4 0
\frac{x + 9}{x^{3} - 9x^{2} + 15x + 25}
\frac{x + 9}{x^{3} - 10x^{2} + x^{2} + 25x - 10x + 25}
\frac{x + 9}{x^{3} - 10x^{2} + 25x + x^{2} - 10x + 25}
\frac{x + 9}{x(x^{2}) - x(10x) + x(25) + 1(x^{2}) - 1(10x) + 1(25)}
\frac{x + 9}{x(x^{2} - 10x + 25) + 1(x^{2} - 10x + 25)}
\frac{x + 9}{(x + 1)(x^{2} - 10x + 25)}
\frac{x + 9}{(x + 1)(x^{2} - 5x - 5x + 25)}
\frac{x + 9}{(x + 1)(x(x) - x(5) - 5(x) + 5(5)}
\frac{x + 9}{(x + 1)(x(x - 5) - 5(x  -5))}
\frac{x + 9}{(x + 1)(x - 5)(x - 5)}
\frac{x + 9}{(x + 1)(x - 5)^{2}}
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3 years ago
Rewrite the expression below.<br><br> -2a( a + b - 5)+ 3 (-5a + 2b) +b (6a + b - 8)
Paul [167]

Answer:

b^2 + 4 a b - 2 b - 2 a^2 + -5 a

Step-by-step explanation:

Simplify the following:

-2 a (a + b - 5) + 3 (2 b - 5 a) + b (6 a + b - 8)

-2 a (-5 + a + b) = 10 a - 2 a^2 - 2 a b:

10 a - 2 a^2 - 2 a b + 3 (2 b - 5 a) + b (6 a + b - 8)

3 (2 b - 5 a) = 6 b - 15 a:

10 a - 2 a^2 - 2 a b + 6 b - 15 a + b (6 a + b - 8)

b (-8 + 6 a + b) = -8 b + 6 a b + b^2:

10 a - 2 a^2 - 2 a b - 15 a + 6 b + -8 b + 6 a b + b^2

Grouping like terms, 10 a - 2 a^2 - 2 a b - 15 a + 6 b - 8 b + 6 a b + b^2 = b^2 + (6 a b - 2 a b) + (6 b - 8 b) - 2 a^2 + (10 a - 15 a):

b^2 + (6 a b - 2 a b) + (6 b - 8 b) - 2 a^2 + (10 a - 15 a)

a b 6 + a b (-2) = 4 a b:

b^2 + 4 a b + (6 b - 8 b) - 2 a^2 + (10 a - 15 a)

6 b - 8 b = -2 b:

b^2 + 4 a b + -2 b - 2 a^2 + (10 a - 15 a)

10 a - 15 a = -5 a:

Answer:  b^2 + 4 a b - 2 b - 2 a^2 + -5 a

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if a value is negative, is a liability, you're below water, -50, you owe 50 bucks, you're in the hole for 50 clams.

so Jackson owes Monica $15, he's in the hole for 15 bucks, namely his balance with his sister is -15.

if he pays her $1, he owes her 14, so -14 is his balance, let's make a quick table of that

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