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Anettt [7]
3 years ago
7

Rewrite the expression below. -2a( a + b - 5)+ 3 (-5a + 2b) +b (6a + b - 8)

Mathematics
1 answer:
Paul [167]3 years ago
8 0

Answer:

b^2 + 4 a b - 2 b - 2 a^2 + -5 a

Step-by-step explanation:

Simplify the following:

-2 a (a + b - 5) + 3 (2 b - 5 a) + b (6 a + b - 8)

-2 a (-5 + a + b) = 10 a - 2 a^2 - 2 a b:

10 a - 2 a^2 - 2 a b + 3 (2 b - 5 a) + b (6 a + b - 8)

3 (2 b - 5 a) = 6 b - 15 a:

10 a - 2 a^2 - 2 a b + 6 b - 15 a + b (6 a + b - 8)

b (-8 + 6 a + b) = -8 b + 6 a b + b^2:

10 a - 2 a^2 - 2 a b - 15 a + 6 b + -8 b + 6 a b + b^2

Grouping like terms, 10 a - 2 a^2 - 2 a b - 15 a + 6 b - 8 b + 6 a b + b^2 = b^2 + (6 a b - 2 a b) + (6 b - 8 b) - 2 a^2 + (10 a - 15 a):

b^2 + (6 a b - 2 a b) + (6 b - 8 b) - 2 a^2 + (10 a - 15 a)

a b 6 + a b (-2) = 4 a b:

b^2 + 4 a b + (6 b - 8 b) - 2 a^2 + (10 a - 15 a)

6 b - 8 b = -2 b:

b^2 + 4 a b + -2 b - 2 a^2 + (10 a - 15 a)

10 a - 15 a = -5 a:

Answer:  b^2 + 4 a b - 2 b - 2 a^2 + -5 a

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5 0
3 years ago
C(n)=-6+5(n-1)<br> find the 8th term in this sequence
Goryan [66]

Answer:

29

Just replace n by 8 ===> C(8) = -6+5(8-1) = - 6 + 5x7 = -6+35 = 29

Step-by-step explanation:

We have been given a sequence formula. We are asked to find the 8th term of our given sequence.

We know that an arithmetic sequence is in form A_n=a_1+(n-1)d, where,

A_n=\text{ nth term of sequence},

A_1=\text{ 1st term of sequence},

n = Number of terms in sequence,

d = Common difference.

To find the 8th term of our given sequence, we will substitute n=8 in our given formula.

c(n)=-6+5(n-1)

c(8)=-6+5(8-1)

c(8)=-6+5(7)

c(8)=-6+35

5 0
3 years ago
Please answer ASAP. The question is down below.
Butoxors [25]

Answer:  1) c     2) d

<u>Step-by-step explanation:</u>

Use Pythagorean Theorem to find the hypotenuse (r):  x² + y² = r²

Given: x = 2, y = 6

                2² + 6² = r²

                4 + 36 = r²

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                      \sqrt{40}=r

\sin \theta=\dfrac{y}{r}\quad =\large\boxed{\dfrac{6}{\sqrt{40}}}\quad \rightarrow \dfrac{6}{2\sqrt{10}}\quad \rightarrow \dfrac{3}{\sqrt{10}}

*******************************************************************************************

\sin \theta = \dfrac{opposite(y)}{hypotenuse(r)}\quad =\dfrac{12}{20}\quad \rightarrow \dfrac{3}{5}\quad \rightarrow \large\boxed{0.6}\\\\\\\cos \theta = \dfrac{adjacent(x)}{hypotenuse(r)}\quad =\dfrac{16}{20}\quad \rightarrow \dfrac{4}{5}\quad \rightarrow \large\boxed{0.8}

5 0
3 years ago
Brainliest for first answer that is correct! Please help ASAP question on photo attached
USPshnik [31]

Answer:

EH


Step-by-step explanation:

Since this is a parallelogram the side of the bottom quadrilateral must be parallel so EH must be parallel to FG

5 0
3 years ago
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mote1985 [20]
75 divided by 6 is 12.5
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you round 12.5 up to 13
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3 years ago
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