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Drupady [299]
3 years ago
12

One liter is approximately equal to 0.26 gallons. Find the volume rounded to the nearest hundredth of a gallon of a container th

at holds approximately 107.2 liters.
Mathematics
2 answers:
guapka [62]3 years ago
4 0

Answer:

<h2>The container holds around 27.9 gallons.</h2>

Step-by-step explanation:

Givens

  • 1 liter is approximately 0.26 gallons.

Now, the container holds 107.2 liters approximately. To know this volume in gallons, we just need to transform using the given ratio 1L=0.26gal

So, if 1 liter is around 0.26 gallons, how much gallons would be 107.2 liters?

x=107.2L\frac{0.26gal}{1L} =27.9 gal

Therefore, the container holds around 27.9 gallons.

Leni [432]3 years ago
3 0
107.2×.26= 27.87 gallons
107.2 liters, .26 gallons per liter
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Select True or False to correctly classify each inequality.
Ksivusya [100]
<h2><u><em>Answer:</em></u></h2>

<u><em>1. FALSE</em></u>

<u><em>2. TRUE</em></u>

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<u><em>4. TRUE</em></u>

<h2>Step-by-step explanation:</h2>

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3 0
3 years ago
Use​ Newton's method to find an approximate solution of ln(x)=10-x. Start with x_0 =9 and find x_2 .
vova2212 [387]

Answer:

x₂ = 7.9156

Step-by-step explanation:

Given the function  ln(x)=10-x with initial value x₀ = 9, we are to find the second approximation value x₂ using the Newton's method. According to Newtons method xₙ₊₁ = xₙ -  f(xₙ)/f'(xₙ)

If f(x) = ln(x)+x-10

f'(x) = 1/x + 1

f(9) = ln9+9-10

f(9) = ln9- 1

f(9) = 2.1972 - 1

f(9) = 1.1972

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x₁ = 9 -  1.1972/1.1111

x₁  = 9 - 1.0775

x₁  = 7.9225

x₂ = x₁ -  f(x₁)/f'(x₁)

x₂ = 7.9225 -  f(7.9225)/f'(7.9225)

f(7.9225) = ln7.9225 + 7.9225 -10

f(7.9225) = 2.0697 + 7.9225 -10

f(7.9225) = 0.0078

f'(7.9225) = 1/7.9225 + 1

f'(7.9225) = 0.1262+1

f'(7.9225) = 1.1262

x₂ = 7.9225 - 0.0078/1.1262

x₂ = 7.9225 - 0.006926

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7 0
3 years ago
9. Five times a number is the same as the number added to five. What is the<br> number?
Alenkinab [10]
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=======

Check:

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Hope it helps . Note that I am a sixth grade student and I don’t know anything . I got help from somebody
4 0
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