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finlep [7]
3 years ago
5

Help ! 6th grade math on coordinate plane !

Mathematics
1 answer:
cestrela7 [59]3 years ago
3 0

800 ..................

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the expression 5n + 2 can be used to find the total cost in dollars of bowling where n is the number of games bowled and the 2 i
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5(3)+2
15+2
17 monies

Just plug the amount of games in for n
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3 years ago
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Rate of change for y= 2/3x-48
tangare [24]

Answer:

2/3

Step-by-step explanation:

The rate of change is the same thing as the slope of a line

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2 years ago
If 5<2x+3<11, what is the possible range of value of -4x-6
Lady bird [3.3K]

Answer:

-10 > (-4x - 6) > -22

Step-by-step explanation:

Given inequality is 5 < 2x + 3 < 11

Now we will multiply this inequality by (-2) resulting,

5(-2) > (2x + 3)(-2) > 11(-2)

-10 > (-4x - 6) > -22 (Sign of inequality gets reversed when the inequality is multiplied or divided by a negative number)

Therefore, the possible range of (-4x - 6) is between -22 and -10.

4 0
3 years ago
Exercise 6.13 presents the results of a poll evaluating support for the health care public option in 2009, reporting that 52% of
sleet_krkn [62]

Answer:

A sample size of 6755 or higher would be appropriate.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error M is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

52% of Independents in the sample opposed the public option.

This means that p = 0.52

If we wanted to estimate this number to within 1% with 90% confidence, what would be an appropriate sample size?

Sample size of size n or higher when M = 0.01. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.01 = 1.645\sqrt{\frac{0.52*0.48}{n}}

0.01\sqrt{n} = 0.8218

\sqrt{n} = \frac{0.8218}{0.01}

\sqrt{n} = 82.18

\sqrt{n}^{2} = (82.18)^{2}

n = 6754.2

A sample size of 6755 or higher would be appropriate.

3 0
3 years ago
You accidentally dropped a coin from the top of 7 stairs. What is the probability that it will land below the sixth step and hea
Sergeeva-Olga [200]
1/7 * 1/2 = 1/14
1/2 because there is a 50/50% chance its either heads or tails 
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