Question

What is (n4+18n3+36n2)÷9n2

Answer 1

1/9n^2+2n+4 is your answer 

Answer 2

$\frac{n^4+18n^3+36n^2}{9n^2}$
we can factor out a n² on top
$\frac{n^2(n^2+18n+36)}{9n^2}$
cancel ones (the n² on top and bottom)
$\frac{n^2+18n+36}{9}$
we can split the top up
remember
(a+b)/c=(a/c)+(b/c)
$\frac{n^2+18n+36}{9}$=
$\frac{n^2}{9}+\frac{18n}{9}+\frac{36}{9}$=
$\frac{n^2}{9}+2n+4$
that is nicest form