Answer:
yes
Step-by-step explanation:
by the side and letgh
4 x^2 + 28 x + 49 = 0
Divide both sides by 4:
x^2 + 7 x + 49/4 = 0
Write the left hand side as a square:
(x + 7/2)^2 = 0
Take the square root of both sides:
x + 7/2 = 0
Subtract 7/2 from both sides:
Answer: x = -7/2
Let the four numbers be A,B,C,D in ascending order.
The key is in conditions 2 & 3.
B-C=-4, and B+C=0
therefore B=-2, C=2 by solving the two previous equations.
Given that the product of the two greatest numbers is 6, we have C*D=6, or
D=6/C=6/2=3
Now since the sum of all the four numbers is -6, we have
A+B+C+D=-6
A-2+2+3=-6
A=-6+2-2-3=-9
Check: we were told smallest divided by greatest = A/D=-9/3=-3 ok.
So the numbers are
A=-9, B=-2, C=2, D=3.
Well basically what you need to do is dta
Add 4 to both sides to cancel out the -4 on the left.
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