The value of K for which f(x) is a valid probability density function is 1/4.
<h3>How to solve for the value of K</h3>
![K[\frac{2^2}{2} -0]+[K[4(4-2)-(\frac{4^2}{2} -\frac{2^2}{2} )]=1](https://tex.z-dn.net/?f=K%5B%5Cfrac%7B2%5E2%7D%7B2%7D%20-0%5D%2B%5BK%5B4%284-2%29-%28%5Cfrac%7B4%5E2%7D%7B2%7D%20-%5Cfrac%7B2%5E2%7D%7B2%7D%20%29%5D%3D1)
open the equation
![K\frac{4}{2}+K[8 - (\frac{16}{2} -\frac{4}{2} )] = 1\\](https://tex.z-dn.net/?f=K%5Cfrac%7B4%7D%7B2%7D%2BK%5B8%20-%20%28%5Cfrac%7B16%7D%7B2%7D%20%20-%5Cfrac%7B4%7D%7B2%7D%20%29%5D%20%3D%201%5C%5C)
![2K+K[\frac{4}{2} ]=1](https://tex.z-dn.net/?f=2K%2BK%5B%5Cfrac%7B4%7D%7B2%7D%20%5D%3D1)
2K + 2K = 1
4K = 1
divide through by 4
K = 1/4
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1 plus 1 equals 2 ,2 times 0 equals 0 .get it.
First, we get ax^2+bx+c. Next, we know that the line of symmetry is -b/2a. Since we know that there is a maximum value, the parabola is facing downwards, so a is negative. For random numbers, we can say that a = -0.5 and b=-10 (b needs to be negative for -b/2a to equal -10), getting -0.5x^2-10x+c. Plugging -10 in for x (since -10 is the middle it is the max), we get -50+100=50. Since the maximum needs to be 5, not 50, we subtract 45 from the answer to get it and therefore make c = -45, getting -0.5x^2-10x-45
Answer: put the parallelograms in the box that says 2 pairs of parallel sides next put the squares in the box that says 4 right angles the put rectangles in the box that says 4 congruent sides and last put rhombuses in the middle box that says 4 right angles and 4 congruent sides
Step-by-step explanation:
