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kolbaska11 [484]
3 years ago
7

On Wednesday at 9 a.m., Winston went diving. Near the beach, the ocean’s surface was at an elevation of -2.5 feet. During his de

epest dive, Winston reached an elevation that was 20 1/5 times the elevation of the ocean’s surface. What elevation did Winston reach during his deepest dive?
Mathematics
1 answer:
Elden [556K]3 years ago
7 0
20.2 * -2.5ft = -50.5ft

Hence, Winston reach -50.5 feet during his deepest dive.
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(04.01)
otez555 [7]

Answer:

A function can be any set of points where one input is equal to one output. You cannot have two X values with the same Y value, for example.

<u>I believe the answer is neither</u> because in both sets you can see they have different Y values for the X values 2 and 9.

6 0
3 years ago
Which of the following are solutions to the equation below?
Natasha2012 [34]
Both A and C would be solutions to the equation.

In order to solve for this you must first get the equation equal to 0. 

2x^2+5x+8=6 ----> subtract 6 from both sides
2x^2 + 5x + 2 = 0

Now knowing this we can use the coefficients of each one in descending order of power as a, b and c. 

a = 2 (because it is the coefficient to x^2)
b = 5 (because it is the coefficient to x)
c = 2 (because it is the end number)

Now we can plug these values into the quadratic equation. 

\frac{-b +/- \sqrt{b^{2} - 4ac } }{2a}

\frac{-5 +/- \sqrt{5^{2} - 4(2)(2) } }{2(2)}

\frac{-5 +/- \sqrt{9} }{4}

\frac{-5 +/- 3 }{4}

\frac{-5 + 3 }{4} or -1/2 for the first answer

\frac{-5 - 3 }{4} or -2 for the second answer

5 0
3 years ago
Using the graphing tool, determine the function for the graph that passes through the points (2.1,2.4), (4.3,6.8), and (6.1,1.9)
Paha777 [63]

Answer:

  f(x) = -1.18056x² +9.55556x -12.4604

Step-by-step explanation:

As required by the problem statement, technology was used to find the polynomial function that passes through the given points. The coefficients shown above are rounded to 6 significant figures. The exact coefficients appear to be ...

  f(x) = (-1 13/72)x² +(9 5/9)x -(12 221/480)

8 0
3 years ago
Read 2 more answers
A production process produces 2% defective parts. a sample of 5 parts from the production is selected. what is the probability t
Lana71 [14]

Answer:

Probability of a sample that contains exactly two defective parts is .0037 or .37%

Step-by-step explanation:

As we know if P is the probability of achieving k results in n trials then probability formula is P = \binom{n}{k}p^{K}q^{n-k}

In this formula n = number of trials

                        k = number of success

                        (n-k) = number of failures

                         p = probability of success in one trial

                         q = (1-p) = probability of failure in one trial

In this sum n = 5

                  k = 2

number failures (n-k) = (5-2) = 3

                            p = 2% which can be written as .02

                            q = 98% Which can be written as .98

Now putting these values in the formula

                        P = \binom{5}{2}(.02)^{2}(.98)^{5-2}

                        P = \binom{5}{2}(.02)^{2}(.98)^{3}

                   \binom{5}{2}= 5!/3!2!    

                                              = 5×4×3×2×1/3×2×1×2×1

                                              = 5×2 =10

                                       P = 10×(.02)²×(.98)³

                                          = .0037 or .37%

4 0
3 years ago
Read 2 more answers
A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks along the x-axis from the spotlight toward the bui
Sedbober [7]

Answer:

0.675 m/s

Step-by-step explanation:

Let height of shadow= y,CD=x

Height of man=2 m

Speed of man= \frac{dx}{dt}=1. 8 m/s

\triangle ABD\sim\triangle ECD

Therefore, \frac{AB}{EC}=\frac{BD}{CD}

\frac{y}{2}=\frac{12}{x}

xy=24

Differentiate w.r.t t

x\frac{dy}{dt}+y\frac{dx}{dt}=0

x\frac{dy}{dt}=-y\frac{dx}{dt}

\frac{dy}{dt}=-\frac{y}{x}\frac{dx}{dt}

When the man is 4 m from  the building

Then, we have x=12-4=8 m

\frac{dx}{dt}=1.8 m/s

Substitute the values in above equation then, we get

8y=24

y=\frac{24}{8}=3

Substitute the values then we get

\frac{dy}{dt}=-\frac{3}{8}\times 1.8=-0.675 m/s

Hence, the length of his shadow on the building decreasing at the rate 0.675 m/s.

8 0
3 years ago
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