Answer:
A function can be any set of points where one input is equal to one output. You cannot have two X values with the same Y value, for example.
<u>I believe the answer is neither</u> because in both sets you can see they have different Y values for the X values 2 and 9.
Both A and C would be solutions to the equation.
In order to solve for this you must first get the equation equal to 0.
2x^2+5x+8=6 ----> subtract 6 from both sides
2x^2 + 5x + 2 = 0
Now knowing this we can use the coefficients of each one in descending order of power as a, b and c.
a = 2 (because it is the coefficient to x^2)
b = 5 (because it is the coefficient to x)
c = 2 (because it is the end number)
Now we can plug these values into the quadratic equation.





or -1/2 for the first answer

or -2 for the second answer
Answer:
f(x) = -1.18056x² +9.55556x -12.4604
Step-by-step explanation:
As required by the problem statement, technology was used to find the polynomial function that passes through the given points. The coefficients shown above are rounded to 6 significant figures. The exact coefficients appear to be ...
f(x) = (-1 13/72)x² +(9 5/9)x -(12 221/480)
Answer:
Probability of a sample that contains exactly two defective parts is .0037 or .37%
Step-by-step explanation:
As we know if P is the probability of achieving k results in n trials then probability formula is P = 
In this formula n = number of trials
k = number of success
(n-k) = number of failures
p = probability of success in one trial
q = (1-p) = probability of failure in one trial
In this sum n = 5
k = 2
number failures (n-k) = (5-2) = 3
p = 2% which can be written as .02
q = 98% Which can be written as .98
Now putting these values in the formula
P = 
P = 
= 5×4×3×2×1/3×2×1×2×1
= 5×2 =10
P = 10×(.02)²×(.98)³
= .0037 or .37%
Answer:
0.675 m/s
Step-by-step explanation:
Let height of shadow= y,CD=x
Height of man=2 m
Speed of man= 

Therefore, 


Differentiate w.r.t t



When the man is 4 m from the building
Then, we have x=12-4=8 m

Substitute the values in above equation then, we get


Substitute the values then we get

Hence, the length of his shadow on the building decreasing at the rate 0.675 m/s.