This is the graph for the problem
That will be 29.5
Hopefully it’s right
Since we want just the top 20% applicants and the data is normally distributed, we can use a z-score table to check the z-score that gives this percentage.
The z-score table usually shows the percentage for the values below a certain z-score, but since the whole distribution accounts to 100%, we can do the following.
We want a z* such that:
But, to use a value that is in a z-score table, we do the following:
So, we want a z-score that give a percentage of 80% for the value below it.
Using the z-score table or a z-score calculator, we can see that:
![\begin{gathered} P(zNow that we have the z-score cutoff, we can convert it to the score cutoff by using:[tex]z=\frac{x-\mu}{\sigma}\Longrightarrow x=z\sigma+\mu](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20P%28zNow%20that%20we%20have%20the%20z-score%20cutoff%2C%20we%20can%20convert%20it%20to%20the%20score%20cutoff%20by%20using%3A%5Btex%5Dz%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5CLongrightarrow%20x%3Dz%5Csigma%2B%5Cmu)
Where z is the z-score we have, μ is the mean and σ is the standard deviation, so:
so, the cutoff score is approximately 72.
Answer:
18 pages per hour.
If you do 36 (the pages/amount) divided by 2 (The time), you get 18.
To double check, when you do 90 (The pages/amount) divided by 5 ( The time), then you get 18 again.
Therefore the answer is 18 pages per hour.
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I figured out the answer Chaseashley24! The answer to your question is:
0.673 m/s²
Hope this helps!
