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OverLord2011 [107]
3 years ago
14

what is the standard deviation of the following data? if necessary, round your answer to two decimal places. 100, 140, 130, 180,

80, 160
Mathematics
1 answer:
frez [133]3 years ago
8 0
The standard deviation of the following data is <span>33.87</span>
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9.1÷3576 rounded to the nearest whole number
Mice21 [21]

Answer:

Answer is 0

Step-by-step explanation:

\frac{9.1}{3576}=0.0025447427

Whole numbers are the set of numbers represented by {0,1,2,3.......}, So basically counting numbers with a 0. Whole numbers does not contain fractions or negative numbers.

Rounding off is a way of simplifying a number so that it is close to the value of the original number. 0.0025447427 lies in between the whole number 0 and 1. But is is a very small value and is close to 0 than 1. So the closet whole number is 0.

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3 years ago
50 POINTS! + BRAINLIEST! ANSWER ASAP
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C it is 1,-6 jjjjjjjjj
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HELLLLPPPPPLPPOOLL no fake answers pls
stepan [7]

Answer:

x = 11

Step-by-step explanation:

(3x + 28) + (5x + 52) + ( 2x - 10) = 180

(3x + 5x + 2x) + (28 + 52 - 10) = 180

10x + 70 = 180

10x = 180 - 70

10x = 110

x = 11

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3 years ago
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In decimal form, to the nearest tenth, what is the probability that a randomly selected Riverside High School student is in twel
Lunna [17]
We have that the total students there are 500. The 12-graders there are 200. Probability is defined as the ratio of positive outcomes of an event, over all the possible outcomes. Suppose we pick student randomly. Then, there are 200 positive outcomes (positive outcome: we pick a student in 12th grade) and there are totally 500 outcomes (we can pick 500 students in total from Riverside High School). This ratio gives: P= \frac{200}{500} =0.4. The requested probability is 0.40
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3 years ago
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9/20
Stella [2.4K]

<u>Question:</u>

Find the number of real number solutions for the equation. x^2 + 5x + 7 = 0

<u>Answer:</u>

The number of real solutions for the equation x^{2}+5 x+7=0 is zero

<u>Solution:</u>

For a Quadratic Equation of form : a x^{2}+b x+c=0  ---- eqn 1

The solution is x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}  

Now , the given Quadratic Equation is x^{2}+5 x+7=0  ---- eqn 2

On comparing Equation (1) and Equation(2), we get

a = 1 , b = 5 and c = 7

In x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a} , b^2 - 4ac is called the discriminant of the quadratic equation

Its value determines the nature of roots

Now, here are the rules with discriminants:

1) D > 0; there are 2 real solutions in the equation

2) D = 0; there is 1 real solution in the equation

3) D < 0; there are no real solutions in the equation

Now let solve for given equation

D= b^2 - 4ac\\\\D = 5^2 - 4(1)(7)\\\\D = 25 - 28 \\\\D = -3

Since -3 is less than 0, this means that there are 0 real solutions in this equation.

4 0
4 years ago
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