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OverLord2011 [107]

3 years ago

14

what is the standard deviation of the following data? if necessary, round your answer to two decimal places. 100, 140, 130, 180,

80, 160

1 answer:

frez [133]3 years ago

8 0

The standard deviation of the following data is <span>33.87</span>

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Geometry question. please help

Vinvika [58]

Answer:

The length of PQ is <u>18</u> feet.

The length of PR is <u>18</u> feet.

The length of QR is <u>24</u> feet.

Step-by-step explanation:

A way to set an equation up for this problem is:

$\frac{4}{3}x+x+x=60$

where x is the three lengths of the isosceles triangle, but the base QR is 4/3 the length of the other two congruent sides, length PQ and PR. The 60 represents the total length of the perimeter.

Then, solve for x from the equation, and you’ll get x=18. But your not done yet. Since the variable x in the equation stands for the sides of the isosceles triangle, so plug 18 into the equation and it should look like this:

$\frac{4}{3}(18)+18+18=60$

Don’t solve the whole equation, just solve the $\frac{4}{3}(18)$ part of the equation, which is equal to 24. So the final equation is this:

$24+18+18=60$

Conclusion: 24 is the length of QR, and 18 is the length of PQ and PR. And they all equal 60, which is the perimeter. This is very true because the length of PQ and PR are the same (length 18), since it’s an isosceles triangle, and the length of QR is 4/3 the length of PQ and PR (4/3 of 18= 24).

Sorry for the long explanation.

But hope this helps and answers your question :)

8 0

3 years ago

Help please! I have choral practice...

Maslowich

<span>This polygon is composed of a right triangle and <span>a parallelogram.

The area of right angle :
$A_\Delta=\frac{1}{2}\cdot15\cdot8=\frac{1}{2}\cdot120=\boxed{60\ (cm^2)}$

The area of the </span></span><span>parallelogram</span>:
$A_P=15\cdot(13-8)=15\cdot5=\boxed{75\ (cm^2)}$

The area of the polygon is equal: $A=A_\Delta+A_P$

Therefore, the answer is:
$\boxed{\boxed{A=60\ cm^2+75\ cm^2=135\ cm^2}}$

7 0

3 years ago

Read 2 more answers

Triangle ABL is an isosceles triangle in circle A with a radius of 11, PL = 16, and ∠PAL = 93°. Find the area of the circle encl

katovenus [111]

Answer:

The area of the circle enclosed by line PL and arc PL is approximately 37.62 square units

Step-by-step explanation:

The given parameters in the question are;

The radius of the circle, r = 11

The length of the chord PL = 16

The measure of angle ∠PAL = 93°

The segment of the circle for which the area is required = Minor segment PL

The shaded area of the given circle is the minor segment of the circle enclosed by line PL and arc PL

The area of a segment of a circle is given by the following formula;

Area of segment = Area of the sector - Area of the triangle

In detail, we have;

Area of segment = Area of the sector of the circle that contains the segment) - (Area of the isosceles triangle in the sector)

Area of a sector = (θ/360)×π·r²

Where;

r = The radius of the circle

θ = The angle of the sector of the circle

Plugging in the the values of <em>r</em> and <em>θ</em>, we get;

The area of the sector enclosed by arc PL and radii AP and AL = (93°/360°) × π × 11² ≈ 98.2 square units

Area of a triangle = (1/2) × Base length × Height

Therefore;

The area of ΔAPL = (1/2) × 16 × 11 × cos(93°/2) ≈ 60.58 square units

∴ The area of the segment PL ≈ (98.2 - 60.58) square units = 37.62 square units

Therefore, the area of the shaded segment PL ≈ 37.62 square units

More examples on area of a shaded segment can be found here:

brainly.com/question/22599425

8 0

3 years ago

Read 2 more answers

I can earn coins

Airida [17]

Answer:

28 because he loaned ant how loaning gos

6 0

3 years ago

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• Paul has 5 pencils, each x inches in length. When she lines up the pencils end to end, they measure 34.5 inches. Select all th

IgorC [24]

Answer:

B and C

Step-by-step explanation:

Both of these equationa can be used to find the length of each pencil

6 0

3 years ago