Answer:
time = 28 years
Step-by-step explanation:
Given,
principal amount = $10,000
rate = 4%
total amount = $30,000
According to compound interest formula
where, A = total amount
P = principal amount
r = rate
t = time in years
so, from the question we can write,
by taking log on both sides, we will get
=> log3 = t.log(1.04)
=> t = 28.01
So, the time taken to get the amount from 10000 to 30000 is 28 years.
Part A=B
part B=1480
if you add them up and multiply by 6 you get 1020
2500-1020=1440
Answer: f(x) = x/2 + 4.
where f(x) is the number of stamps that Tom has, and x is the number of stamps that Myrna has.
Step-by-step explanation:
The statement is:
"Tom has four more than half the stamps that Myrna has"
For how is written, we can model the number of stamps that Tom has as a function f(x).
f(x) represents the number of stamps that Tom has, and x is the number of stamps that Myrna has.
Then:
"four more than a number" is written as:
N + 4 (where N is the number)
"Half the stamps that Myrna has" is written as:
x/2.
Then the whole statement can be modeled as:
f(x) = x/2 + 4.
notice that we have x/2, and f(x) must be a whole number, so Myrna must have an even number of stamps (in that case x/2 will be integer)
First, let's calculate the area of the rectangle. Find the distances between the length and the width. For the width we can use point A and point D.
(2, 2) and (20, 2)
20 - 2 = 18
So the width is 18 cm. Now find the length. We can use point A and point B.
(2, 2) and 2, 26)
26 - 2 = 24
So the length is 24.
So the area of the rectangle is 432 square centimeters, now let's find the area of the circle.
The radius is given as 15 cm. Use 3.14 to approximate for pi.
So the area of the circle is approximately 706.5 square centimeters. Subtract this area from the area of the rectangle to find the value of the shaded area.
The initial deceleration is 4 m/s^2, so this means that considering the first line segment, .
The total distance traveled is 4 km, which is equal to 4000 meters. This is equal to the area under the graph, so .