Let n be the number of sides of a polygon.
To solve for the sum of the interior angles:
(n-2) x 180°
To solve for the measure of each interior angle of the polygon
[(n-2) x 180°] / n
To solve for the measure of each exterior angle:
360° / n
The sum of the exterior angles is always 360°
See attachment for answers.
5
The slope-intercept form is y = m x + b y = m x + b , where m m is the slope and b b is the y-intercept. y = m x + b y = m x + b
Rewrite in slope-intercept form.
Subtract 3 x 3 x from both sides of the equation. − 8 y = 5- 3 x - 8 y = 5-3 x
Divide each term by −8 -8 and simplify. y = 3 x 8 − 58 y = 3 x 8 - 58
Rewrite in slope-intercept form. y = 38 x − 58 .
<span>given tan theta 4/3 and sin (-4/5), find cos theta
cos theta-3/5</span>
Answer: sorry this is to hard
Step-by-step explanation: