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kherson [118]
2 years ago
11

These polygons are similar. Find the value of z.

Mathematics
1 answer:
vazorg [7]2 years ago
7 0

Answer:

10

Step-by-step explanation:

Find the two similar sides which are already measured.

6 and 9 are those numbers.

Use similarity proportional ratio:

6/9 = z/15

Cross multiply:

9z = 15 × 6

9z = 90

z = 90 ÷ 9

z = 10

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What is y + 2/5 y equivalent to
Lerok [7]
7/5y. you add the 2/5y to the 5/5y and get 7/5y
8 0
3 years ago
A football team lost five yards on each of two consecutive plays. Find the total change in yardage.
maria [59]

Answer:

The change is a loss of 10 yards, so -10 yards.

Step-by-step explanation:

The total change in yardage after 2 plays is the sum of the yardage of each play.

What lost yardage means?

Lost yardage means negative yardage.

Imagine that in a Buffalo Bills game, Devin Singletary lost 2 yards on his first carry. So his total yardage is -2.

If in the next carry he gets 3 yards, his total yardage is 1. If he loses 1, his total yardage is -3.

First play

Loss of 5 yards.

So the first play counts for -5 yards.

Second play

Loss of 5 yards.

So the second play counts for -5 yards.

Total

-5 - 5 = -10

The change is a loss of 10 yards, so -10 yards.

8 0
2 years ago
A bag contains 2 5/8 pounds of candy. If the candy is equally distributed to point
nirvana33 [79]
The correct answer is 3/8
6 0
2 years ago
elizabeth and success buy books from 2 different book shop, elizabeth bought 4 books for £28, sucess bought 7 book for £63 who h
earnstyle [38]

Answer:

Elizabeth got the better deal

Step-by-step explanation:

Elizabeth bought 4 books for £28 = £28/4 = £7 per book

Success bought 7 books for £63 = £63/7 = £9 per book

7 0
3 years ago
How to do both 14) and 16) b/c I have no idea. It is solving rational equations.
Vinvika [58]
Just like at any other time, to add/subtract fractions you need a common denominator.

14)

1/(x^2+2x)+(x-1)/x=1  so we need a common denominator of x(x^2+2x)

[1(x)]/(x(x^2+2x))+[(x-1)(x^2+2x)]/(x(x^2+2x))=[1(x(x^2+2x))]/(x(x^2+2x))

now if you multiply both sides of the equation by x(x^2+2x) you are left with:

x+(x-1)(x^2+2x)=x(x^2+2x)

x+x^3+2x^2-x^2-2x=x^3+2x^2

x^3+x^2-x=x^3-2x^2

x^2-x=-2x^2

3x^2-x=0

x(3x-1)=0, x=0 is an extraneous solution as division by zero is undefined. So the only real solution is:

x=1/3

...

16)

(r+5)/(r^2-2r)-1=1/(r^2-2r)  the common denominator we need r^2-2r so

[r+5-1(r^2-2r)]/(r^2-2r)=1/(r^2-2r), multiplying both sides by r^2-2r yields:

r+5-r^2+2r=1

-r^2+3r+5=1

-r^2+3r+4=0

r^2-3r-4=0

(r-4)(r+1)=0, r^2-2r cannot equal zero, r(r-2)=0, r cannot equal 0 or 2...

r=-1 or 4
8 0
3 years ago
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