Simplify 3x² × 4x³ ÷ 2x

Help with this exponential function!

butalik [34]

The population size after 6 years and after 8 years are 147 and 169 population respectively

<h3>Exponential functions</h3>

The standard exponential function is expressed as y = ab^x

where

a is the base

x is the exponent

Given the function that represents the population size P (t) of the species as shown;

$p(t)=\frac{550}{1+5e^{-0.1t}} \\$

For the population size after 6 years

$p(t)=\frac{550}{1+5e^{-0.1(6)}} \\P(6)=\frac{550}{3.744}\\ P(6)=147 population$

For the population after 8 years

$p(t)=\frac{550}{1+5e^{-0.1(8)}} \\P(8)=\frac{550}{3.2466}\\ P(8)=169 population$

Hence the population size after 6 years and after 8 years are 147 and 169 population respectively

Learn more on exponential function here: brainly.com/question/2456547

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7 0

2 years ago

26. Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics

hjlf

The test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

<h3>What are null hypotheses and alternative hypotheses?</h3>

In null hypotheses, there is no relationship between the two phenomenons under the assumption or it is not associated with the group. And in alternative hypotheses, there is a relationship between the two chosen unknowns.

Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics course.

Then they are given a post-test once the professor has concluded lecturing on the material.

Pre-test and post-test scores for 4 students in an elementary statistics class are given below.

Then we have

$\mu _d = \mu _{post} - \mu _{pre}$

Then the null hypotheses and alternative hypotheses will be

H₀: $\mu _d = 0$

Hₐ: $\mu _d > 0$

Then the test statistic will be

$\rm \overline{x} _d = \dfrac{\Sigma x_d}{n} = \dfrac{15+12+10+1}{4}\\\\\overline{x} _d = 9.5$

Then

$\rm S_d = 6.02$

The test statistic value is given by

$\rm t = \dfrac{\overline{x} _d }{\dfrac{S_d}{\sqrtn}} \\\\t = \dfrac{9.5}{\dfrac{6.02}{\sqrt4}}\\\\t = 3.16$

Since this is a right-tailed test, so the critical value is given by

$\rm t_{n-1}(\alpha ) = t_3 (0.05) = 2.353$

Since the test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

Hence, we can conclude that $\mu _d > 0$ that is test scores have improved.

More about the null hypotheses and alternative hypotheses link is given below.

brainly.com/question/9504281

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7 0

2 years ago

Shade the model to 0.5 x 0.3

stellarik [79]

What model? also it would be 1/2 and 1/3

6 0

3 years ago

Read 2 more answers

Can someone please help me!!!!

Otrada [13]

It is true because if a is perpendicular to b and b is perpendicular to c therefore a has to be perpendicular to c also they said that all three lines are coplanar therefore the statement must be true

I hope this helped you out :)

8 0

3 years ago

Ms.Lawrence had 550 in her bank account. The next day she withdrew 120 to buy groceries. She deposited 200 two days later. Fout

hjlf

Answer:

541

Step-by-step explanation:

550-120+200-89=541

7 0

3 years ago