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natali 33 [55]
3 years ago
7

Simplify 3x² × 4x³ ÷ 2x

Mathematics
1 answer:
svp [43]3 years ago
4 0

Answer:

6x^4

Step-by-step explanation:

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Help with this exponential function!
butalik [34]

The population size after 6 years and after 8 years are 147 and 169 population respectively

<h3>Exponential functions</h3>

The standard exponential function is expressed as y = ab^x

where

a is the base

x is the exponent

Given the function that represents the population size P (t) of the species as shown;

p(t)=\frac{550}{1+5e^{-0.1t}} \\

For the population size after 6 years

p(t)=\frac{550}{1+5e^{-0.1(6)}} \\P(6)=\frac{550}{3.744}\\ P(6)=147 population

For the population after 8 years

p(t)=\frac{550}{1+5e^{-0.1(8)}} \\P(8)=\frac{550}{3.2466}\\ P(8)=169 population

Hence the population size after 6 years and after 8 years are 147 and 169 population respectively

Learn more on exponential function here: brainly.com/question/2456547

#SPJ1

7 0
2 years ago
26. Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics
hjlf

The test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

<h3>What are null hypotheses and alternative hypotheses?</h3>

In null hypotheses, there is no relationship between the two phenomenons under the assumption or it is not associated with the group. And in alternative hypotheses, there is a relationship between the two chosen unknowns.

Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics course.

Then they are given a post-test once the professor has concluded lecturing on the material.

Pre-test and post-test scores for 4 students in an elementary statistics class are given below.

Then we have

\mu _d = \mu _{post} - \mu _{pre}

Then the null hypotheses and alternative hypotheses will be

H₀: \mu _d = 0

Hₐ: \mu _d > 0

Then the test statistic will be

\rm \overline{x} _d = \dfrac{\Sigma x_d}{n} = \dfrac{15+12+10+1}{4}\\\\\overline{x} _d = 9.5

Then

\rm S_d = 6.02

The test statistic value is given by

\rm t = \dfrac{\overline{x} _d }{\dfrac{S_d}{\sqrtn}} \\\\t = \dfrac{9.5}{\dfrac{6.02}{\sqrt4}}\\\\t = 3.16

Since this is a right-tailed test, so the critical value is given by

\rm t_{n-1}(\alpha ) = t_3 (0.05) = 2.353

Since the test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

Hence, we can conclude that \mu _d > 0 that is test scores have improved.

More about the null hypotheses and alternative hypotheses link is given below.

brainly.com/question/9504281

#SPJ1

7 0
2 years ago
Shade the model to 0.5 x 0.3
stellarik [79]
What model? also it would be 1/2 and 1/3
6 0
3 years ago
Read 2 more answers
Can someone please help me!!!!
Otrada [13]

It is true because if a is perpendicular to b and b is perpendicular to c therefore a has to be perpendicular to c also they said that all three lines are coplanar therefore the statement must be true

I hope this helped you out :)

8 0
3 years ago
Ms.Lawrence had 550 in her bank account. The next day she withdrew 120 to buy groceries. She deposited 200 two days later. Fout
hjlf

Answer:

541

Step-by-step explanation:

550-120+200-89=541

7 0
3 years ago
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