Answer:
10 terms
Step-by-step explanation:
equate the sum formula to 55 and solve for n
n(n + 1) = 55 ( multiply both sides by 2 to clear the fraction )
n(n + 1) = 110 ← distribute parenthesis on left side
n² + n = 110 ( subtract 110 from both sides )
n² + n - 110 = 0 ← in standard form
Consider the factors of the constant term (- 110) which sum to give the coefficient of the n- term (+ 1)
the factors are + 11 and - 10 , since
11 × - 10 = - 110 and 11 - 10 = + 1 , then
(n + 11)(n - 10) = 0 ← in factored form
equate each factor to zero and solve for n
n + 11 = 0 ⇒ n = - 11
n - 10 = 0 ⇒ n = 10
However, n > 0 , then n = 10
number of terms which sum to 55 is 10
Answer:
33.75.
Step-by-step explanation:
The mean = sum of the numbers / the number count
= (34 + 31 + 32 + 38) / 4
= 135 / 4
= 33.75.
-11111111122647373738374848384747374747477347474
Answer:
f(-2/3) = -1
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = 3x + 1
f(-2/3) is x = -2/3
<u>Step 2: Evaluate</u>
- Substitute: f(-2/3) = 3(-2/3) + 1
- Multiply: f(-2/3) = -2 + 1
- Add: f(-2/3) = -1
Answer:
I think they are SAS but I'm not sure
