Answer:
210 people are there at the fair
Step-by-step explanation:
Let the total number of people at the fair = X
People under 16 years old = 70% of X = 0.7 X
People remaining = Total number of people - Under 16 years
= X - 0.7X = 0.3X
The number of teachers = 1/3 of People remaining = 1/3 of 0.3X
Since there are 21 teachers
1/3 of 0.3X = 21
1/3 x 0.3X = 21
0.1X = 21
Divide both sides by the coefficient of X
0.1X/0.1 = 21/0.1
X = 210
That is 210 people are there at the fair
<span>23.24 seconds.
The travel time from the start of the trip to the end will have three phases. Initial acceleration, cruising, and deceleration. So, let's see how long each phase takes. For the initial acceleration phase, assume it accelerates at 4.50m/s2 until it reaches 19.8 m/s. So calculate t.
t = 19.8 m/s / 4.5 m/s2 = 19.8/4.5 s = 4.4 s
The distance traveled during the acceleration phase will be 1/2AT^2. So
d = 0.5 * 4.5 * t^2 = 2.25 * 4.4^2 = 2.25 * 19.36 = 43.56 m
The deceleration phase will also take 4.4 seconds and occur over a distance of 43.56 m. So the combined distance for acceleration and deceleration is 43.56 * 2 = 87.12 meters.
Now the total distance that we want to travel is 373 m. So you can determine the distance for the cruising phase by subtracting the combined distances for acceleration and deceleration. Giving
cruise = 373 - 87.12 = 285.88 m
The time the cruising phase takes is the distance divided by the speed, so we get
t = 285.88 m / 19.8 m/s = 14.44 seconds.
Finally, the total travel time is the time for acceleration plus time for cruising plus time for deceleration, giving
4.4 s + 14.44 s + 4.4 s = 23.24 seconds.</span>
Answer:
3
Step-by-step explanation:
Answer:
f(x)=x^2+3x+2
Step-by-step explanation:
The answer is B !!!!!!!!!!!
