Answer:
PR = 34.4
Step-by-step explanation:
x/54 = 7/11
11x = 378
x = 34.4
Answer : 0.0129
Step-by-step explanation:
Given : Based on FAA estimates the average age of the fleets of the 10 largest U.S. commercial passenger carriers is years and standard deviation is years.
Sample size :
Let X be the random variable that represents the age of fleets.
We assume that the ages of the fleets of the 10 largest U.S. commercial passenger carriers are normally distributed.
For z-score,
For x=14
By using the standard normal distribution table , the probability that the average age of these 40 airplanes is at least 14 years old will be :-
Hence, the required probability = 0.0129
(13x^2 - 10x + 12) - (9x^2 + 20x - 50)
13x^2 - 10x + 12 - 9x^2 - 20x + 50
13x^2 - 9x^2 = <em>4x^2</em>
- 10x - 20x = <em>-30x</em>
12 + 50 = <em>62</em>
4x^2 - 30x + 62
Step-by-step explanation:
if area is = 10mm *18mm = 180mm2
Answer: D
Step-by-step explanation: