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almond37 [142]
3 years ago
13

Convert -36 degrees to radians

Mathematics
2 answers:
Pepsi [2]3 years ago
7 0

Answer:

-36(π/180) = - π/ 5

Step-by-step explanation:

The answer is - (π/5)

dimulka [17.4K]3 years ago
3 0
-36 degrees = 0.62831853 radians

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on the stock exchange, 100 shares of pizzazz corp. stock are selling $425. how many shares can be purchased for $1000?
Natali5045456 [20]

Answer:

235.29 shares can be purchased for $1000.

Step-by-step explanation:

As

  • On the stock exchange, 100 shares of pizzazz corp. stock are selling $425

We have to determine how many shares can be purchased for $1000?

The price of 100 shares = $425

The price of 1 share = 425/100 = $4.25

Now, It is very easy to calculate the number of shares can be purchased for $1000.

All you have to do is to divide by 1000 by 4.25.

i.e.  1000/4.25 = 235.29 shares

Therefore, 235.29 shares can be purchased for $1000.

6 0
4 years ago
Multiply. (3.6 × 10^-9 ) • (4,500,000)
Lady bird [3.3K]
24 rounded to the nearest 7
5 0
3 years ago
Find an equivalent expression to 3(4m-2)-2(m+5)
Anuta_ua [19.1K]
3(4m-2)-2(m+5)

Distribute. 

12m-6-2m-10

12m-2m= 10m

-6-10= -16

10m-16

I hope this helps!
~kaikers
3 0
3 years ago
34xy What are the factors of the expression?<br> 3/4,<br> -1,<br> 4,<br> x,<br> y,
grandymaker [24]
The factors of this expression are 34, x, and y.
7 0
3 years ago
If N is the population of the colony and t is the time in​ days, express N as a function of t. Consider Upper N 0 is the origina
lesya [120]

Answer:

(a)N(t)=Noe^{kt}

(b)5,832 Mosquitoes

(c)5 days

Step-by-step explanation:

(a)Given an original amount N_o at t=0. The population of the colony with a growth rate k \neq 0, where k is a constant is given as:

N(t)=Noe^{kt}

(b)If N_o=1000 and the population after 1 day, N(1)=1800

Then, from our model:

N(1)=1800

1800=1000e^{k}\\$Divide both sides by 1000\\e^{k}=1.8\\$Take the natural logarithm of both sides\\k=ln(1.8)

Therefore, our model is:

N(t)=1000e^{t*ln(1.8)}\\N(t)=1000\cdot1.8^t

In 3 days time

N(3)=1000\cdot1.8^3=5832

The population of mosquitoes in 3 days time will be approximately 5832.

(c)If the population N(t)=20,000,we want to determine how many days it takes to attain that value.

From our model

N(t)=1000\cdot1.8^t\\20000=1000\cdot1.8^t\\$Divide both sides by 1000\\20=1.8^t\\$Convert to logarithm form\\Log_{1.8}20=t\\\frac{Log 20}{Log 1.8}=t\\ t=5.097\approx 5\; days

In approximately 5 days, the population of mosquitoes will be 20,000.

7 0
3 years ago
Read 2 more answers
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